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jenyasd209 [6]
2 years ago
9

What is the product?

Mathematics
1 answer:
makkiz [27]2 years ago
4 0

Step-by-step explanation:

(4s + 2) × (5s² + 10s +3)

we know immediately the first and the last term of the result, because there is only one operation to build them :

20s³ and 6.

so, the first answer option is already eliminated.

let's multiply

4s×5s² + 4s×10s + 4×3s + 10s² + 20s + 6

20s³ + 40s² + 12s + 10s² + 20s + 6

20s³ + 50s² + 32s + 6

so, the last answer option is correct.

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Someone please help my with my geometry test?!!!
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Answer:

what is the question

Step-by-step explanation:

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2 years ago
find the interest earned on an account with $450 principal, and interest rate of 6% over a period of 8 years
puteri [66]
 
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450(1+.06)  = 717.23
4 0
3 years ago
In 2015 the population of 895 quail increases at an annual rate of 3.5%. In writing an
spayn [35]

Answer:

y=895•1.07^x Y is the population of quails and X is the amount of years that have passed.

Step-by-step explanation:

hope this helps

7 0
3 years ago
Can anyone help me with this
stepladder [879]

Answer:

D

Step-by-step explanation

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8 0
3 years ago
A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)
DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

Speed=\frac{distance}{time}

in this problem we have

distance=400\ m \\time=120\ sec

substitute in the formula

Speed=\frac{400}{120}

Speed=3.5\frac{m}{sec}

therefore

<u>the answer Part a) is</u>

the speed is equal to 3.5\frac{m}{sec}

<u>Part b) </u>Find the velocity

we know that

<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

magnitude=3.5\frac{m}{sec}

direction=North\ East\ (NE)

therefore

<u>the answer Part b) is</u>

the velocity is 3.5\frac{m}{sec}\ North\ East\ (NE)

Part c)

we know that

the acceleration is equal to the formula

a=\frac{V2-V1}{t2-t1}

in this problem we have

V2=0 \\V1=3.5\frac{m}{sec}

t2=15\ sec\\t1=0

substitute in the formula

a=\frac{0-3.5}{15-0}

a=-\frac{3.5}{15}\frac{m}{sec^{2}}

a=-\frac{7}{30}\frac{m}{sec^{2}}

therefore

<u>the answer Part c) is</u>

the acceleration is -\frac{7}{30}\frac{m}{sec^{2}}

This is an example of negative acceleration

7 0
3 years ago
Read 2 more answers
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