False because, If you have to move the decimal point to the right to get the original number, the exponent will be a positive number, if you have to move the decimal point to the left to get the original number, the exponent will be a negative number.
<span>Answer:
let x = shortest base of the trapezoid
A = h (x/2 + r) = âš(r² - (x/2)²) (r + x/2)
= âš(1 - (x/2)²) (1 + x/2) .... if r = 1
dA/dx = (2 - x - x²) / (2âš(4 - x²))
= 0 at x = 1 .... which is a relative maximum because d²A/dx² < 0
A = (3/4) âš3</span>
The sum of two irrational numbers<span> is SOMETIMES </span>irrational<span>. The </span>sum of two irrational numbers<span>, in some cases, will be </span>irrational. However, if the irrational<span> parts of the </span>numbers<span> have a zero </span>sum<span>(cancel each other out), the </span>sum<span> will be </span>rational<span>. But Remember the sum of two irrational number is sometimes irrational. Hope this helped :)</span>
Answer:
It has no real solutions.
Step-by-step explanation
Once you calculate the discriminant, D= (-10)^2 -4 (8)(15), you simplify the expression to get D= -380, which has no real solutions.
It would be 5 2/15 as 3/5 = 9/15. 14 - 9 = 5. 9/15 - 7/15 = 2/15 so 5 2/15
