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2 years ago

Uno de los componentes del “sal de uvas”, es el bicarbonato de sodio, es un sólido cristalino blanco, debido a

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Uno de los componentes del “sal de uvas”, es el bicarbonato de sodio, es un sólido cristalino blanco, debido a su capacidad de neutralizar el exceso de ácido clorhídrico del estómago.

La acidez estomacal es ocasionada por un exceso en la producción de ácido clorhídrico (HCl) en el jugo gástrico del estómago. Uno de los componentes del “sal de uvas”, utilizada como antiácido, es el bicarbonato de sodio (NaHCO₃), es un sólido cristalino blanco, que neutraliza el exceso de ácido clorhídrico. La reacción de neutralización es:

HCl(aq) + NaHCO₃(aq) ⇒ NaCl(aq) + H₂O(l) + CO₂(g)

Puedes aprender más sobre neutralización aquí: brainly.com/question/23261152

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Need help ASAP!<br><br> How many moles of sodium nitrate are in 0.25 L of 1.2 M NaNO3 solution?

Setler79 [48]

Answer:

$\boxed {\boxed {\sf 0.3 \ mol \ NaNO_3}}$

Explanation:

Molarity is a measure of concentration in moles per liter.

$molarity= \frac{moles \ of \ solute}{liters \ of \ solution}$

The molarity of the solution is 1.2 M NaNO₃ or 1.2 moles NaNO₃ per liter. There are 0.25 liters of the solution. The moles of solute are unknown, so we can use x.

molarity= 1.2 mol NaNO₃/L
liters of solution=0.25 L
moles of solute =x

$1.2 \ mol \ NaNO_3/L= \frac{x}{0.25 \ L}$

We are solving for x, so we must isolate the variable, x. It is being divided by 0.25 liters. The inverse of division is multiplication, so we multiply both sides by 0.25 L.

$0.25 \ L *1.2 \ mol \ NaNO_3/L=\frac{x}{0.25 \ L} *0.25 \ L$

$0.25 \ L *1.2 \ mol \ NaNO_3/L=x$

The units of liters cancel, so we are left with the units moles of sodium nitrate.

$0.25 *1.2 \ mol \ NaNO_3=x$

$0.3 \ mol \ NaNO_3=x$

There are 0.3 moles of sodium nitrate.

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2 years ago