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Alexeev081 [22]
3 years ago
15

The ph of a finished water from a water treatment process is 10.74. What amount of .02 n sulfuric acid, in milliliters, is requi

red to neutralize 1 l of finished water assuming alkalinity is zero
Chemistry
1 answer:
MAVERICK [17]3 years ago
3 0

The pH of water is given to be 10.74.

This means = pOH = 14 - pH = 3.26

pOH = -log[OH-]= 3.26

[OH-] = 0.00055 M / N

The concentration of H2SO4 is given to be = 0.02 N

volume of water = 1 L

So moles of OH- = number of equivalents of OH-

                     = concentration X volume (L) = 0.00055  X 1 = 0.00055

So number of equivalents of H2SO4 requried = 0.00055

Hence volume of 0.02 N H2SO4 required = Moles / Molarity

                     = 0.00055/0.02 = 0.0275 L = 27.5 mL


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Answer:

I don't know if you can directly prove it with evidence if you haven't observed it but you can maybe take an educated guess by the aftermath of it?

For example, you see a burnt log. At this time, people don't know what fire is. After we study the log, we could see that it takes extreme temperature in order to burn the log and that would help people see that there is a force like fire that can cause this. In a way, finding out that extreme temperatures burns stuff is another step closer to the discovery and proof of fire

I hope that makes sense

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A mole of cars stacked end to end would stretch back and forth across the United States how many times? Measured length of 1 car
vekshin1

Answer:

i am potato

Explanation:

4444141+5-45458/85*55474

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2 years ago
Acids reacts with base and produces salt and water represent it in the form of chemical equation
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HCl+ NaoH- Nacl+H2O

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base react with acid

3 0
3 years ago
How many carbon atoms are there in .500 mol of CO2?
AURORKA [14]

Answer: There are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

In a molecule of CO_{2} there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of CO_{2} are as follows.

1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}

Thus, we can conclude that there are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

6 0
2 years ago
A solution of sodium hydroxide (NaOH) was standardized against potassium hydrogen phthalate (KHP). A known mass of KHP was titra
Eddi Din [679]

Answer:

See explanation below

Explanation:

In order to calculate this, we need to use the following expression to get the concentration of the base:

MaVa = MbVb (1)

We already know the volume of NaOH used which is 13.4473 mL. We do not have the concentration of KHP, but we can use the moles. We have the mass of KHP which is 0.5053 g and the molecular formula. Let's calculate the molecular mass of KHP:

Atomic weights of the elements to be used:

K = 39.0983 g/mol;  H = 1.0078 g/mol;  C = 12.0107 g/mol;  O = 15.999 g/mol

MM KHP = (1.0078*5) + (39.0983) + (8*12.0107) + (4*15.999) = 204.2189 g/mol

Now, let's calculate the mole of KHP:

moles = 0.5053 / 204.2189 = 0.00247 moles

With the moles, we also know that:

n = M*V (2)

Replacing in (1):

n = MbVb

Now, solving for Mb:

Mb = n/Vb  (3)

Finally, replacing the data:

Mb = 0.00247 / (13.4473/1000)

Mb = 0.184 M

This would be the concentration of NaOH

8 0
3 years ago
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