Answer:
The second run will be faster - true, the increased surface area of catalyst will increase the rate of reaction
The second run will have the same rate as the first - possible, in case there is a factor other than catalyst limiting the reaction
The second run has twice the surface area - yes, 44 sqcm to 22 sqcm
Explanation:
A catalyst is a material which speeds up a reaction without being consumed in the process. A heterogeneous catalyst is one which is of a different phase than the reactants. The effectiveness of a catalyst is dependent on the available surface area. The first step for this question is to determine the total available surface area of catalyst in both processes.
Step 1: Determine radius of large sphere
![V_{L}=\frac{4}{3}*pi*{r_{L}}^{3}](https://tex.z-dn.net/?f=V_%7BL%7D%3D%5Cfrac%7B4%7D%7B3%7D%2Api%2A%7Br_%7BL%7D%7D%5E%7B3%7D)
![10=\frac{4}{3}*pi*{r_{L}}^{3}](https://tex.z-dn.net/?f=10%3D%5Cfrac%7B4%7D%7B3%7D%2Api%2A%7Br_%7BL%7D%7D%5E%7B3%7D)
![{r_{L}}^{3}=\frac{7.5}{pi}](https://tex.z-dn.net/?f=%7Br_%7BL%7D%7D%5E%7B3%7D%3D%5Cfrac%7B7.5%7D%7Bpi%7D)
![r_{L}=1.337cm](https://tex.z-dn.net/?f=r_%7BL%7D%3D1.337cm)
Step 2: Determine surface area of large sphere
![A_{L}=4*pi*{r_{L}}^{2}](https://tex.z-dn.net/?f=A_%7BL%7D%3D4%2Api%2A%7Br_%7BL%7D%7D%5E%7B2%7D)
![A_{L}=4*pi*1.337^{2}](https://tex.z-dn.net/?f=A_%7BL%7D%3D4%2Api%2A1.337%5E%7B2%7D)
![A_{L}=22.463 cm^{2}](https://tex.z-dn.net/?f=A_%7BL%7D%3D22.463%20cm%5E%7B2%7D)
Step 3: Determine radius of small sphere
![V_{s}=\frac{4}{3}*pi*{r_{s}}^{3}](https://tex.z-dn.net/?f=V_%7Bs%7D%3D%5Cfrac%7B4%7D%7B3%7D%2Api%2A%7Br_%7Bs%7D%7D%5E%7B3%7D)
![1.25=\frac{4}{3}*pi*{r_{s}}^{3}](https://tex.z-dn.net/?f=1.25%3D%5Cfrac%7B4%7D%7B3%7D%2Api%2A%7Br_%7Bs%7D%7D%5E%7B3%7D)
![{r_{s}}^{3}=\frac{0.9375}{pi}](https://tex.z-dn.net/?f=%7Br_%7Bs%7D%7D%5E%7B3%7D%3D%5Cfrac%7B0.9375%7D%7Bpi%7D)
![r_{s}=0.668cm](https://tex.z-dn.net/?f=r_%7Bs%7D%3D0.668cm)
Step 4: Determine surface area of small sphere
![A_{s}=4*pi*{r_{s}}^{2}](https://tex.z-dn.net/?f=A_%7Bs%7D%3D4%2Api%2A%7Br_%7Bs%7D%7D%5E%7B2%7D)
![A_{s}=4*pi*0.668^{2}](https://tex.z-dn.net/?f=A_%7Bs%7D%3D4%2Api%2A0.668%5E%7B2%7D)
![A_{s}=5.607 cm^{2}](https://tex.z-dn.net/?f=A_%7Bs%7D%3D5.607%20cm%5E%7B2%7D)
Step 5: Determine total surface area of 8 small spheres
![A_{S}=8*A_{s}](https://tex.z-dn.net/?f=A_%7BS%7D%3D8%2AA_%7Bs%7D)
![A_{S}=8*5.607](https://tex.z-dn.net/?f=A_%7BS%7D%3D8%2A5.607)
![A_{S}=44.856 cm^{2}](https://tex.z-dn.net/?f=A_%7BS%7D%3D44.856%20cm%5E%7B2%7D)
- Surface area of 1 large sphere
- Surface area of 8 small spheres
Options:
- The second run will be faster - true, the increased surface area of catalyst will increase the rate of reaction
- The second run will be slower - false, the increased surface area of catalyst will increase the rate of reaction
- The second run will have the same rate as the first - possible, in case there is a factor other than catalyst limiting the reaction
- The second run has twice the surface area - yes, 44 sqcm to 22 sqcm
- The second run has eight times the surface area - no, 44 sqcm to 22 sqcm
- The second run has 10 times the surface area - no, 44 sqcm to 22 sqcm
The three mass value measure are precise mass
<u>explanation</u>
precise mass is term use to describe data from experiment that have been repeated several times. An experiment that yield tightly grouped set of data it has a high precision. 8.93 , 8.94 and 8.92 are precise mass since they have repeated severally
Following laboratory safety protocols such as wearing personal protective equipment will protect John when the accident occurred.
<h3>What are laboratory safety protocols?</h3>
Laboratory safety protocols are the protocols put in place to ensure safety in the laboratory.
Laboratory safety protocols include the following:
- always wear personal protective equipment in the laboratory
- do not play in the laboratory
- do not eat in the laboratory
Following laboratory safety protocols will help protect us from accidents which occur in the laboratory.
What happened when john was carefully pouring a chemical into a beaker when the beaker slips and breaks is an example of laboratory accident.
Wearing personal protective equipment will protect John.
In conclusion, following laboratory safety protocols will protect us when accidents occur in the laboratory.
Learn more about laboratory safety protocols at: brainly.com/question/17994387
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Note that the complete question is given as follows:
John is carefully pouring a chemical into a beaker when the beaker slips and breaks. How would laboratory safety protocols help John?
Answer:
C, B ,A(in the order of the blanks)
Explanation:
A centrifuge uses centrifugal force to seperate 2 substances with different densities, the lighter one at the top. This cannot be done with homogeneous mixtures