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antiseptic1488 [7]
3 years ago
12

Help me please????????​

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
8 0

9514 1404 393

Answer:

  A, C, E

Step-by-step explanation:

The proportional relations on the list are ...

  • feet and inches
  • flour and bread
  • gallons and cost

We often model running distance and time as proportional, but a marathon is a long enough run that speed is rarely constant. It usually decreases over the course, and may increase near the end.

__

A relationship is proportional if there is a constant multiplier that relates the output to the input.

_____

<em>Additional comment</em>

For the relations listed above, the constants are ..

  • the conversion factor between feet and inches
  • the amount of flour in a bread recipe
  • the price of a gallon of gas

For running time and distance, the multiplier is <em>speed</em>. The relation is only proportional if speed is a constant.

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ruslelena [56]

Answer:

a) 25.14% of the population is over 6ft tall.

b) Both are going to be normally distributed.

Centimeters: \mu = 177.8, \sigma = 7.62cm

Meters: \mu = 1.778, \sigma = 0.0762cm

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Normally distributed with parameters \mu = 70, \sigma = 3.

a.What proportion of the population is over 6 ft. tall?

We have to convert from ft to inches.

Each feet has 12 inches, so 6ft = 72in.

This proportion is 1 subtracted by the pvalue of Z when X = 72. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{72 - 70}{3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

This means that 1-0.7486 = 0.2514 = 25.14% of the population is over 6ft tall.

b.What is the distribution of heights if they are expressed in centimeters? Inmeters?

It is going to still be normally distributed. We just have to convert the mean and the standard deviation from inches to centimeters and meters.

In centimeters.

Each inch has 2.54cm. So it is going to be normally distributed with \mu = 70*2.54 = 177.8cm and \sigma = 3*2.54 = 7.62xm

In meters

Each m has 100cm. So

\mu = 1.778m, \sigma = 0.0762m.

7 0
4 years ago
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