Answer:
Q = 2647 J
Explanation:
Specific heat capacity is the amount of energy required by one Kg of a substance to raise its temperature by 1 °C.
In thermodynamics the equation used is as follow,
Q = m Cp ΔT
Where;
Q = Heat = ?
m = mass = 660 g
Cp = Specific Heat Capacity = 0.3850 J.g⁻¹.°C⁻¹
ΔT = Change in Temperature = 23.35 °C - 12.93 °C = 10.42 °C
Putting values in eq. 1,
Q = 660 g × 0.3850 J.g⁻¹.°C⁻¹ × 10.42 °C
Q = 2647 J
Sulfuric acid is prepared industrially by means of the response of water with sulfur trioxide which in turn is made by way of a chemical combination of sulfur dioxide and oxygen both by way of the touch system or the chamber system.
H2SO4 (l) H2O (g) + SO3 (g).
The reaction is highly exothermic as an enormous amount of heat is liberated.
The usual approach is to dilute the sulfur trioxide in sulphuric acid. This produces oleum. SO3 (g) + H2SO4 → H2S2O7 (1) Oleum can be in addition diluted in water to acquire concentrated sulphuric acid.
An acid catalyst is added to protonate the carbonyl carbon. How does this catalyze the response, robust acid catalysts catalyze the hydrolysis and transesterification of esters which enables the mechanism with a view to boom the electrophilicity of the carbonyl carbon to assist protonate the carbonyl oxygen.
Learn more about sulfuric acid here:-brainly.com/question/11857977
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Use Avogadro's number which is numerically equal to ...
( 6.02 multiply by 10 to the power of negative 23)
Avocado's number is the number of particle(molecules, ions, atoms) present in one mole of substance.
number of molecule in 0.809 mole of h20 = ....
one mole of h20 contains (6.02* 10^-23)
0.809 mole contains....(6.02* 10^-23) (0.809)
which is equal to [4.951* 10 ^-23]
if I made no mistake in calculation...it must be correct
M.P of oleic acid = 13 deg C
<span>B.Pof oleic acid = 360 deg C </span>
<span>(360 - 13) / 100 = 3.47 </span>
<span>So 1 deg O = 3.47 deg C </span>
<span>The scale do not start at 0 deg C, it starts at 13 deg C. So to convert deg C to deg O,
subtract 13 then divide by 3.47 </span>
<span>deg O = (deg C - 13) / 3.47 </span>
<span>convert O to C multiply by 3.47 then add 13 </span>
<span>deg C = (deg O x 3.47) + 13 </span>
<span>convert 0 deg C to deg O </span>
<span>deg O = (0 deg C - 13) / 3.47 </span>
<span>= - 3.75 deg O</span>
The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applies to an acid-base titration.
moles NaOH = c · V = 0.2423 mmol/mL · 32.23 mL = 7.809329 mmol
moles H2SO4 = 7.809329 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.9046645 mmol
Hence
[H2SO4]= n/V = 3.9046645 mmol / 37.21 mL = 0.1049 M
The answer to this question is [H2SO4] = 0.1049 M
