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maw [93]
3 years ago
7

What is gamma rays burst​

Chemistry
2 answers:
zlopas [31]3 years ago
8 0

Answer:

In gamma-ray astronomy, gamma-ray bursts are immensely energetic explosions that have been observed in distant galaxies. They are the brightest and most energetic electromagnetic events known to occur in the universe. Bursts can last from ten milliseconds to several hours.

A gamma-ray burst will emit the same amount of energy as a supernova, caused when a star collapses and explodes, but in seconds or minutes rather than weeks. Their peak luminosities can be 100 billion billion times that of our sun, and a billion times more than even the brightest supernovas.

storchak [24]3 years ago
6 0

Answer:

In gamma-ray astronomy, gamma-ray bursts are immensely energetic explosions that have been observed in distant galaxies. They are the brightest and most energetic electromagnetic events known to occur in the universe. Bursts can last from ten milliseconds to several hours. b

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You might be interested in
Which is the most reactive metal
Lena [83]

The most reactive metal on the periodic table is Francium, However, Francium is an artificial element and only minimal quantities have been produced, so for all practical purposes, the most reactive metal available is Cesium, in the alkali metal family.


ANSWER In theory, Francium, in practice the Cesium


\textbf{Spymore}​

8 0
3 years ago
Determine the number of 3s electrons in Na .
Scorpion4ik [409]

Answer:

Explanation:The atomic number of sodium is 11. That is, the number of electrons in sodium is 11. Therefore, a sodium atom will have two electrons in the first shell, eight in the 2nd orbit, and an electron in the 3rd shell.

3 0
1 year ago
A certain shade of blue has a frequency of 7.08×1014 Hz. What is the energy of exactly one photon of this light? Planck's consta
Anvisha [2.4K]

Answer:

We have the final answer as

4.69 \times  {10}^{ - 19}  \:  \:  J

Explanation:

To find the energy of a photon of this light we use the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 7.08×10¹⁴ Hz

We have

E = 7.08×10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

4.69 \times  {10}^{ - 19}  \:  \:  J

Hope this helps you

8 0
3 years ago
The pKa of formic acid is 3.75. At pH of 5.00, _______ .
AlladinOne [14]

The pKa of formic acid is 3.75. At pH of 5.00, b) [formate] > [formic acid].

Formic acid is a weak acid. Thus, together with its conjugate base (formate) they form a buffer system. We can calculate the pH of a buffer system using Henderson-Hasselbach's equation.

pH = pKa + log \frac{[formate]}{[formic\ acid]} \\\\5.00 = 3.75 + log \frac{[formate]}{[formic\ acid]}\\\\\frac{[formate]}{[formic\ acid]}  = 17.8

As expected, at a pH above the pKa, the concentration of formate is higher than that of the formic acid.

The pKa of formic acid is 3.75. At pH of 5.00, b) [formate] > [formic acid].

Learn more: brainly.com/question/22821585

5 0
3 years ago
5. A compound with a formula of lead (Pb) and sulfur (S) was determined using the method in this experiment. A sample of Pb was
Airida [17]

Answer:

The mass of S that reacted is 0.642g

Explanation:

In this case we have

⇒ mass of crucible and cover, 25.429g

⇒ mass of crucible, cover, and Pb, 29.465g

⇒ mass of crucible, cover and commass of crucible and coverpound formed, 30.107g

The mass of Pb reacted = mass of crucible, cover, and Pb - mass of crucible and cover = 29.465 - 25.429 = 4.036g

The mass of compound formed = mass of crucible, cover and commass of crucible and coverpound formed  - mass of crucible and cover = 30.107 - 25.429g = 4.678g

The mass of S reacted = Mass of compound formed - mass of Pb reacted = 4.678 -4.036 = 0.642g

The mass of S that reacted is 0.642g

7 0
3 years ago
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