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Ahat [919]
3 years ago
6

Which type of equipment would be used to precisely measure 26.0 mL of dilute hydrochloric acid?

Chemistry
2 answers:
VikaD [51]3 years ago
8 0
The type of equipment that would be used to precisely measure 26.0 mL of dilute hydrochloric acid would be C. 50 mL graduated cylinder.
D doesn't have enough mLs to measure this, and A and B have too many. 
icang [17]3 years ago
4 0

Answer: option C

Explanation: Graduated cylinder

Since it gives exact value including significant figures .

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All mixtures can be separated by physical processes. true or false
DaniilM [7]
<span>True. In chemistry, mixtures are two (or more) substances mixed together but not combined chemically. This means there are no chemical bonds that have formed between the substances. As such, they can be separated with physical processes.</span>
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Why did me need to have the same molecules in each bottle? and what would have happened if we didn't use the same molecules?
NNADVOKAT [17]

Answer:

it's just like doing a test grade on children if you give them different tests they might not come up with the same results, the molecules need to be the same or else the experiment will be even.

Explanation:

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2 years ago
An enzyme with molecular weight of 310 kDa undergoes a change in shape when the substrate binds. This change can be characterize
oee [108]

Answer:

(a) r = 6.26 * 10⁻⁷cm

(b) r₂ = 6.05 * 10⁻⁷cm

Explanation:

Using the sedimentation coefficient formula;

s =  M(1-Vρ) / Nf ; where s is sedimentation coefficient, M is molecular weight, V is specific volume of protein, p is density of the solvent, N is Avogadro number, f if frictional force = 6πnr, n is viscosity of the medium, r is radius of particle

s = M ( 1 - Vρ) / N*6πnr

making r sbjct of formula, r =  M (1 - Vρ) / N*6πnrs

Note: S = 10⁻¹³ sec, 1 KDalton = 1 *10³ g/mol, I cP = 0.01 g/cm/s

r = {(3.1 * 10⁵ g/mol)(1 - (0.732 cm³/g)(1 g/cm³)} / { (6.02 * 10²³)(6π)(0.01 g/cm/s)(11.7 * 10⁻¹³ sec)

r = 6.26 * 10⁻⁷cm

b. Using the formula r₂/r₁ = s₁/s₂

s₂ = 0.035 + 1s₁ = 1.035s₁

making r₂ subject of formula; r₂ = (s₁ * r₁) / s₂ = (s₁ * r₁) / 1.035s₁

r₂ = 6.3 * 10⁻⁷cm / 1.035

r₂ = 6.05 * 10⁻⁷cm

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3 years ago
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What is Centripetal force?
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A. A force that acts on a body moving in a circular path

6 0
3 years ago
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