Prove that in general (x + a)<br> 2 ≠ x2 + a2

Christine is 4 years younger than Mark. 3 years from now, she will be two-thirds as old as Mark find their present ages.Complete

icang [17]

Answer:Mark Is 9 years old; Christine is 5 years old

Step-by-step explanation:

Present age

LET mark age be x

Christine be x-4 yrs

In 3 yrs Time

Mark will be x+3 yrs old

Christine will be (x -4 +3) = x-1 years old

Also, In 3 years time

Christine = 2/3 Mark

such that

x-1 = 2/3(x+3)

x -1= 2x+6 / 3

3x -3= 2x+6

3X--2X = 6+3

=X=9

Mark Is 9 years old

Christine is x -4 = 9-4=5 years old

5 0

3 years ago

What is the length of the diagonal, d, of the rectangular prism shown below?

Lena [83]

Answer:

d = 10√10 ≈ 31.62

Step-by-step explanation:

d = √l²+w²+h²

d = √5²+8²+2²

d = √25+81+4

d = √110

d = 10*√10

4 0

3 years ago

Read 2 more answers

Find the nonpermissible replacement for a in this expression 7/6a

vredina [299]

The correct answer for the exercise shown above is:

zero (0)

The explanation is shown below:

1. You have the following expression given in the problem above:

7/6a

2. By definition, <span>the nonpermissible replacement for a is the value that make the denominator equal to zero.

3. Keeping this on mind, you have:

7/6a=7/6(0)=7/0

Therefore, as you can see, the answer is: zero (a=0).

</span>

6 0

3 years ago

Equilateral triangle ABC has a perimeter of 96 millimeters. A perpendicular bisector is drawn from angle A to side Line segment

prisoha [69]

Answer:

Step-by-step explanation:

An equilateral triangle is a triangle that has all of its sides equal.

Perimeter of an equilaterial triangle = 3s where;

s is one side of the triangle.

Given the perimeter of ABC = 96mm

Substituting into the formula above to get s;

96 = 3s

s = 96/3

s = 32mm

Hence the length of one side of the triangle is 32mm

If a perpendicular bisector is drawn from angle A to side Line segment B C at point M, then MC will be half of BC and ΔAMC will be a right angled triangle.

Since all the sides of the triangle are equal, hence BC = 32mm. Since MC is the half of BC, then MC = 1/2 of 32mm

MC = 1/2 * 32mm

MC = 16mm

<em>Hence the length of Line segment MC is 16mm</em>

5 0

3 years ago

Read 2 more answers

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

if

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago

Prove that in general (x + a) 2 ≠ x2 + a2