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3 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics

2 answers:

EastWind [94]3 years ago

7 0

Answer:

1334

Step-by-step explanation:

6⁴ . 2³

1296+8

1334

hjlf3 years ago

4 0

Refer the attachment

Make me as brain liest

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How do you solve this??

marin [14]

Answer:

$a_n=-\frac{9}{4} +\frac{1}{4} *n; \ a_{45}=9.$

Step-by-step explanation:

1. the difference between two sequent term is: 2- 7/4=7/4 - 3/2 = 3/2 - 5/4=... = 1/4.

2. using the value of the calculated difference it is possible to make up the formula of the given sequence ('n' - the number of term):

$a_n=-\frac{9}{4}+\frac{1}{4} n.$

3. for n=45:

$a_{45}=-\frac{9}{4}+45*\frac{1}{4}=9.$

5 0

3 years ago

1. What is the y-intercept in the following equation? Explain. y = 1/2x

Step2247 [10]

The slope-intercept form of the equation of a line is

y = mx + b

where m = slope, and b = y-intercept.

Now compare the form above with what you are given.

y = mx + b
y = 1/2x

You can write your equation as y = 1/2x + 0.

That shows that the slope, m, is 1/2 and the y-intercept, b, is 0.

4 0

4 years ago

Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

Neporo4naja [7]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

★ One of the diagonal = 160 m.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Area each of them [son and daughter] will get.

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Let, ABCD be the rhombus shaped field and each side of the field be $x$

[ All sides of the rhombus are equal, therefore we will let the each side of the field be $x$ ]

Now,

• Perimeter = 400m

$\longrightarrow \tt AB+BC+CD+AD=400m$

$\longrightarrow \tt x + x + x + x=400$

$\longrightarrow \tt 4x=400$

$\longrightarrow \tt \: x = \dfrac{400}{4}$

$\longrightarrow \tt x= \red{100m}$

$\therefore$ Each side of the field = 100m.

Now, we have to find the area each [son and daughter] will get.

So, For $\triangle$ ABD,

Here,

• a = 100 [AB]

• b = 100 [AD]

• c = 160 [BD]

$\therefore \tt Simi \: perimeter \: [S] = \boxed{ \sf \dfrac{a + b + c}{2} }$

$\longrightarrow \tt S = \dfrac{100 + 100 + 160}{2}$

$\longrightarrow \tt S = \cancel{ \dfrac{360}{2}}$

$\longrightarrow \tt S = 180m$

Using herons formula,

$\star \tt Area \: of \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star$

where

• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

Putting the values,

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(80)(80)(20) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180 \times 80 \times 80 \times 20 }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{ {3}^{2} \times {20}^{2} \times {80}^{2} }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = 3 \times 20 \times 80$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \red{ 4800 \: {m}^{2} }$

Thus, area of $\triangle$ ABD = 4800 m²

As both the triangles have same sides

So,

Area of $\triangle$ BCD = 4800 m²

Therefore, area each of them [son and daughter] will get = 4800 m²

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

${\underline{\rule{290pt}{2pt}}}$

7 0

2 years ago

Read 2 more answers

HELP DUE IN 15 MINS!

boyakko [2]

Answer:

r = $2\sqrt{5}$

$(x - 3)^{2} + ( y - 2)^{2} = 20$

Is this a live test question or a homework question?

Step-by-step explanation:

the radius is the distance between (3, 2) and (5, -2)

$r^{2}$ = ${(3 - 5)^{2} + (2 + 2)^{2} }$

= $(-2)^{2} + 4^{2}$

= 4 + 16 = 20

r = $\sqrt{20 } = 2\sqrt{5}$

Equation of circle: $(x - 3)^{2} + ( y - 2)^{2} = 20$

8 0

3 years ago

Read 2 more answers

On a treasure map, the last clue is that the treasure is buried is buried a certain number of feet away from a tree. the distanc

Trava [24]

The lcm of 20 and 8 is 40 feet.

3 0

3 years ago