<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
32x^3+4x^2+41x-35
hope it helps
Answer:
d = 1.46 m
Step-by-step explanation:
We'll begin by obtaining the relationship between the force (F) and the distance (d). This can be obtained as follow:
From the question given above,
F is inversely proportional to square of d. This can be written as:
F ∝ 1/d²
F = K/d²
Cross multiply
K = Fd²
But:
Force (F) = 0.006 N
Distance (d) = 4 m
Constant (K) =?
K = Fd²
K = 0.006 × 4²
K = 0.006 × 16
K = 0.096 Nm²
Therefore, the relationship between the force (F) and the distance (d) is:
F = K/d²
F = 0.096 / d²
Finally, we shall determine the distance when the force is 0.045 N. This can be obtained as follow:
Force (F) = 0.045 N
Constant (K) = 0.096 Nm²
Distance (d) =?
F = K/d²
0.045 = 0.096 / d²
Cross multiply
0.045 × d² = 0.096
Divide both side by 0.045
d² = 0.096 / 0.045
Take the square root of both side.
d = √(0.096 / 0.045)
d = 1.46 m.
Answer:
20%
Step-by-step explanation:
If you see they say that the number decreased is 10% each and they say it two times. we could see that the missing number is as big as the length of two 10% together, so if you add them two you get 20%.
