Answer:
y = 8x + 3
Step-by-step explanation:
The line we are describing here is line p;
slope of line p = 8
y- intercept = (0,3)
y-intercept of a line is the point where it crosses the y-axis. At this point, the x = 0
So;
Slope of the line = 8
y-intercept = 3
Equation of the line;
y = mx + c
y and x are the coordinates
m is the slope
c is the y-intercept
y = 8x + 3
Let that be

Two vertical asymptotes at -1 and 0

If we simply

- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is

Graph attached
It would be 60.
a(b)^x
Since a/ 60 would represent initial value.
Well. I can't see the picture. But it would be decreasing at a rate of 4 so pick a point on the any line move over to the right one, then down four. And for the y intercept the line would intersect the y axis at positive one. Sorry if that's confusing