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ValentinkaMS [17]
2 years ago
10

-10+16 divided by (-2)+7 *Please show work!*

Mathematics
2 answers:
wel2 years ago
8 0

Answer:

= 1 1/5

Step-by-step explanation:

= -10+16/(-2)+7

= 6/5

= 1 1/5

Verdich [7]2 years ago
4 0
Here’s my work to your question!

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Gnom [1K]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Simplify the expression –2(p + 4)2 – 3 + 5p. What is the simplified expression in standard form?
mojhsa [17]

Answer:

-2p² − 11p − 35

Step-by-step explanation:

Simplifying:

-2(p + 4)² − 3 + 5p

-2(p² + 8p + 16) − 3 + 5p

-2p² − 16p − 32 − 3 + 5p

-2p² − 11p − 35

This is also the standard form.

6 0
3 years ago
Read 2 more answers
V^(2)+9v=-14 help me
rjkz [21]
Hello :
v²+9v+14 = 0
(v+2)(v+7) =0
v+2 =0 or v+7 = 0
 v=-2 or v= -7


3 0
3 years ago
(1 pt) A. Find y in terms of x if dydx=x4y−3 and y(0)=5. y(x)= . B. For what x-interval is the solution defined? (Your answers s
saveliy_v [14]

Answer:

y=(\frac{4}{5}x^5+625)^{\frac{1}{4}}

y=f(x)\ x E R (x is all real numbers)

Step-by-step explanation:

A. We have the differential equation

\frac{dy}{dx}=x^4y^{-3}

by using separation of variables we have

y^3dy=x^4dx\\\\\int y^3dy=\int x^4dx\\\\\frac{1}{4}y^4=\frac{1}{5}x^5+C'\\\\y=(\frac{4}{5}x^5+C)^{\frac{1}{4}}

C is the new constant C=4C'

y(0)=(C)^{\frac{1}{4}}=5\\C=625

hence y is

y=(\frac{4}{5}x^5+625)^{\frac{1}{4}}

B.

the interval is calculated by taking into account

y=f(x)^{\frac{1}{4}}=f(x)^{\frac{1}{2}}f(x)^{\frac{1}{2}}

in both factors f(x) can take negative values because i*i=-1 a real number. Hence we have the interval

y=f(x)\ x E R (x is all real numbers)

hope this helps!!

8 0
3 years ago
Square root of 24 divided by square root of 27
spayn [35]

Answer:

= 2/27 square root of 6

Step-by-step explanation:

:)

8 0
4 years ago
Read 2 more answers
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