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slava [35]
3 years ago
11

Type the correct answer in the box. Use numerals instead of words.

Mathematics
1 answer:
alexdok [17]3 years ago
8 0

Answer: n = 6 or you can do n = -6

Step-by-step explanation:

solve for n and then the left hand side factors

into a product with for terms then multiply both sides by -2  then split into two equations after add 6 to both sides and subtract 6 from both sides.

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1. In which quadrant does θ lie given that sinθ>0 and cosθ<0?
expeople1 [14]

Answer:

\theta is in quadrant II

Step-by-step explanation:

Given

\sin(\theta)  > 0 and \cos(\theta)  < 0

Required

Where is \theta

\sin(\theta)  > 0 and \cos(\theta)  < 0 imply that

\theta is in quadrant II

Because that is only quadrant where \sin(\theta)  > 0 and \cos(\theta)  < 0 exist.

4 0
3 years ago
It a picture of the question
salantis [7]
The answer would be less than due to the decimal placing so this
8 0
3 years ago
Please help ill give whoever answers the best the brainliest answer :0
Yuri [45]

Answer:

The bottom graph

Step-by-step explanation:

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3 0
2 years ago
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What is the measure of the angle fgb? Can someone please help asap ill mark brainlist!!!
ddd [48]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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Solve this
ValentinkaMS [17]

\sqrt{33 +  \sqrt{4 +  \sqrt{50 \cos(60°) } } }

  • Now, we know cos(60°) = \frac {1}{2}. So put the value there.

\sqrt{33 +  \sqrt{4 +  \sqrt{50 \times  \frac{1}{2} } } }  \\  =  \sqrt{33 +  \sqrt{4 +  \sqrt{25} } }  \\  =  \sqrt{33 +  \sqrt{4 +  5 } }  \\  =  \sqrt{33 +  \sqrt{9} }  \\  =  \sqrt{33 + 3}  \\  =  \sqrt{36}  \\  = 6

Hence LHS = RHS [Proved]

Hope you could understand.

If you have any query, feel free to ask.

4 0
3 years ago
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