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Sidana [21]
3 years ago
7

Quadrilateral LMNP has been translated to form quadrilateral TVWY. What is the length of YW?

Mathematics
1 answer:
Komok [63]3 years ago
7 0

Answer:

f(x)=4x^3-5

Step-by-step explanation:

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The book costs $49.95 with 3% sales tax. What is the total cost?
VladimirAG [237]

Answer:

74.8

Step-by-step explanation:

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3 years ago
What is the formula to find the measure of each interior angle of a regular polygon
Setler [38]

Answer:

A regular polygon is a flat shape whose sides are all equal and whose angles are all equal. The formula for finding the sum of the measure of the interior angles is (n - 2) * 180. To find the measure of one interior angle, we take that formula and divide by the number of sides n: (n - 2) * 180 / n.

Step-by-step explanation:

There ya go.. :)

7 0
3 years ago
Five-sixths of the distance from 1 to −13
Finger [1]

The distance of 1 to -13 is 14.

Five sixths of this is (.8333*14), which equals 11.6667.

8 0
3 years ago
C = 188.4in <br> What’s the answer
Advocard [28]

Answer:

Well from where the equation is now, I don't see any further things I can do. What is the context of the problem?

Step-by-step explanation:

7 0
3 years ago
A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0
3 years ago
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