The last choice is the correct one
Answer: I'm pretty sure that it´s C but Im not sure.
Sorry if that's wrong.
(6y - 11)(6y + 11) = ay
² - b |use (a - b)(a + b) = a² - b²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
It's three because of you have two anything bigger than two is three