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Setler [38]
3 years ago
15

Derivative of y=(3x+5)^3​

Mathematics
2 answers:
UkoKoshka [18]3 years ago
6 0

\\ \sf\longmapsto \dfrac{dy}{dt}

\\ \sf\longmapsto \dfrac{d}{dt}(3x+5)^3

\\ \sf\longmapsto \{3(3x+5)\}^2

\\ \sf\longmapsto (9x+15)^2

\\ \sf\longmapsto 9x^2+2(9x)(15)+(15)^2

\\ \sf\longmapsto 81x^2+270x+225

olga55 [171]3 years ago
6 0
  • \sf{81x^{2}+270x+225 }

Step-by-step explanation:

y=(3x+5)^3\\\\\dfrac{dy}{dx}=\dfrac{d}{dx}(3x+5)^3\\\\\dfrac{dy}{dx}=3(3x+5)^2×\dfrac{d}{dx}(3x+5)\\\\\dfrac{dy}{dx}=3(3x+5)^2×\dfrac{d}{dx}3x+\dfrac{d}{dx}5\\\\\dfrac{dy}{dx}=3(3x+5)^2×3+0\\\\\dfrac{dy}{dx}=9(3x+5)^2\\\\\dfrac{dy}{dx}=9(9x^2+25+30x)\\\\\dfrac{dy}{dx}=81x^2+270x+225

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Use the row of numbers shown below to generate 12 random numbers between 01 and 99.
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Answer:

Below is the complete step-by-step explanation.

Step-by-step explanation:

Given the row of numbers

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<u>Taking 25060 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
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Seed the number (25060) into your calculator. 25060 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

85 90 62 45 26 97 40 55 67 17 10 32

<u>Taking 12315 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

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Seed the number (12315) into your calculator. 12315 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

33 20 26 68 73 09 46 14 82 74 17 04

<u>Taking 86244 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
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Seed the number (86244) into your calculator. 86244 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

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<u>Taking 97348 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
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Seed the number (97348) into your calculator. 97348 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

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<u>Taking 36173 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

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Seed the number (36173) into your calculator. 36173 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

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Total random numbers to be generates = 12

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Seed the number (32710) into your calculator. 32710 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

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Total random numbers to be generates = 12

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Seed the number (80033) into your calculator. 80033 ➡️ rand

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Total random numbers to be generates = 12

Range of random number generators

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Seed the number (16160) into your calculator. 16160 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

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Keywords: random number generator

Learn more about random number generator from brainly.com/question/1601128

#learnwithBrainly

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Answer:

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Step-by-step explanation:

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The marbles can be modeled as <u>spheres</u>.

<u>Volume of a sphere</u>

\sf V=\dfrac{4}{3}\pi r^3 \quad \textsf{(where r is the radius)}

<u>Radius</u>

\sf r = \dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

Therefore, the volume of 9 marbles, each of diameter 3 inches is:

\sf Volume & = \sf 9 \left(\dfrac{4}{3} \pi (1.5\:in)^3 \right)

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The vase can be modeled as a <u>cylinder</u>.

<u>Volume of a cylinder</u>

\sf V=\pi r^2 h \quad \textsf{(where r is the radius and h is the height)}

Therefore, the volume of a cylinder with a base of diameter 6 in and a height of 12 in is:

\sf Volume =\pi (3\:in)^2(12\:in)

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