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erastovalidia [21]
3 years ago
9

Explain 3 different ways And explain

Mathematics
1 answer:
natta225 [31]3 years ago
5 0

Answer:

5^2 * 5^9

5^3 * 5^8

5^4 * 5^7

Step-by-step explanation:

The easiest way to approach this problem is to first express 5^(11) in its simplest form:

5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5

Then you can regroup them as you want, to still express the same value, but shown as a product of different numbers, including:

(5) * (5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5) = 5 * 5^(10)

(5 * 5) * (5 * 5 * 5 * 5 * 5 * 5 * 5 * 5 * 5) = 5^2 * 5^9

(5 * 5 * 5) * (5 * 5 * 5 * 5 * 5 * 5 * 5 * 5) = 5^3 * 5^8

(5 * 5 * 5 * 5) * (5 * 5 * 5 * 5 * 5 * 5 * 5) = 5^4 * 5^7

And so on....

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Write the equation of a line with a slope of O through the point (3, -1).
jarptica [38.1K]

Answer:

x=3

please mark as brainliest

3 0
3 years ago
A slope of 6 and a point (4,9)
lawyer [7]

The correct answer is

Slope intercept form: y = mx + b

m=6

b=-15

Intercepts:

x-intercept=2.5

y-intercept=-15



6 0
3 years ago
Help idk how to do this ASAP please
Sergio039 [100]

Answer:

The area of ∆DEF = 4.5in²

Step-by-step explanation:

From the above diagram,

∆BAC ~∆DEF

It is important to note that if two triangles are similar, the ratio of their areas is equal or equivalent to the ratio of the areas of their sides

This means for the above question, that

We have the bigger triangle = ∆BAC has a side of 4 in and Area = 8 in²

The small triangle has a side of 3in

Finding the scale factor k = ratio of the sides of both Triangles

k = 4/3

k² = (4/3)²

k² = 16/9

Hence,

Area of ∆BAC/ Area of ∆DEF = 16/9

8in²/Area of ∆DEF = 16/9

We cross Multiply

8 in² × 9 = Area of ∆DEF × 16

Divide both sides by 16

Area of ∆DEF = 72/16

= 4.5in²

Therefore, the Area of ∆DEF rounded to the nearest tenth = 4.5in²

8 0
3 years ago
Find the difference: -2/5-(-4/5)
CaHeK987 [17]

Answer:

2/5

Step-by-step explanation:

-2/5-(-4/5) (remove the parentheses)

-2/5+4/5 (calculate)

solution: 2/5

hope this helps!

5 0
3 years ago
3+-1/1/3 the first half is 3+-1 the second half is 1/3
kolbaska11 [484]
\bf \cfrac{3\pm1}{\frac{1}{3}}\implies 
\begin{cases}
\cfrac{3+1}{\frac{1}{3}}\\\\
\cfrac{3-1}{\frac{1}{3}}
\end{cases}\\\\
-------------------------------\\\\

\bf \cfrac{3+1}{\frac{1}{3}}\implies \cfrac{4}{\frac{1}{3}}\implies \cfrac{\frac{4}{1}}{\frac{1}{3}}\implies \cfrac{4}{1}\cdot \cfrac{3}{1}\implies \cfrac{4\cdot 3}{1\cdot 1}\implies \cfrac{12}{1}\implies \boxed{12}
\\\\\\
\cfrac{3-1}{\frac{1}{3}}\implies \cfrac{2}{\frac{1}{3}}\implies \cfrac{\frac{2}{1}}{\frac{1}{3}}\implies \cfrac{2}{1}\cdot \cfrac{3}{1}\implies \cfrac{2\cdot 3}{1\cdot 1}\implies \cfrac{6}{1}\implies \boxed{6}
6 0
3 years ago
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