For this case, the total amount invested is:
investment = 3500 + 1000 = 4500
We must take out the percentage of what X invested.
X investment = (3500/4500) * 100 = 77.78%.
Therefore, X gets 77.78% of the profits:
X profit = 0.7778 * 3000 = 2333.33 $
answer
if the profits are distributed in proportion to the amount invested X receives 2333.33 $
Answer:
Answer is 3.398
Step-by-step explanation:
Solve by putting into calculator.
Answer: For the sum of 130
First: $90
Second: $40
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.
15a + 5 (130-a)=1550
15a+650-5a=1550
10a+650-650=1550-650
10a=900
a=$90 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
90+b=130
90-90+b=130-90
b= $40 was charged by the second mechanic
If you add 22.80 by the deposit which is 56.60 you will get 79.04
The answer is : 79.04
Answer: 
Step-by-step explanation:
For this exercise it is important to know the definition of "Dilation".
A Dilation is defined as a transformation in which the Image (The figure obtained after the transformation) and the Pre-Image (The original figure before the transformation) have the same shape but have different sizes.
If the Dilation is centered at the origin, and knowing the scale factor of 
, you need to multiply each coordinate of the point T by the scale factor in order to find the coordinates of the Image T'.
Knowing that the point T has the following coordinates:
You get that the coordinates of the Image T' are the shown below:
