1 year ago

How do i solve this?

Mathematics

1 answer:

vazorg [7]1 year ago

3 0

Usually I would use my head, but you can use whatever you want.

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AC = 16, AB = x + 1, and BC = x + 7. What is the measure of the length of AB? HELP

saveliy_v [14]

Answer:

Step-by-step explanation:

AC=AB+BC

so 16=x+1+x+7

which simplifies to 16=2x+8

subtract eight from both sides to get 8=2x

then divide by 2 to get that x=4

AB=x+1, which substitutes into 4+1=5

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2 years ago

Solve each of the following quadratic equations 3x=0.5x^2 0=5x^2-2x+6

UNO [17]

Question 1

$3x=0.5x^{2}\\\\6x=x^{2} \\ \\ x^{2}-6x=0 \\ \\ x(x-6)=0 \\ \\ \boxed{x=0, 6}$

Question 2

$0=5x^{2}-2x+6 \\ \\ x=\frac{2 \pm \sqrt{(-2)^{2}-4(5)(6)}}{2} \\ \\ x=\frac{2 \pm \sqrt{-116}}{10} \\ \\ x=\frac{2 \pm 2i\sqrt{29}}{10} \\ \\ \boxed{x=\frac{1 \pm i\sqrt{29}}{5}}$

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1 year ago

Let f (x) = 1/x and g(x) = x² – 3x. What two numbers are not in the domain of fºg?

iren [92.7K]

For this case we have the following equations:

$f (x) = \frac {1} {x}\\g (x) = x ^ 2-3x$

We must find $(f_ {o} g) (x):$

By definition of composition of functions we have to:

$(f_ {o} g) (x) = f (g (x))$

So:

$(f_ {o} g) (x) = \frac {1} {x ^ 2-3x}$

We must find the domain of f (g (x)). The domain will be given by the values for which the function is defined, that is, when the denominator is nonzero.

$x ^ 2-3x = 0\\x (x-3) = 0$