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2 years ago

If the order of a matrix A is 2×3 and order of AB is 2×4 then, find the order of matrix B.

Mathematics

1 answer:

marshall27 [118]2 years ago

4 0

I think it’s 2x1 hope this helps

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) Find the coordinates of the point A' which is the symmetric point

soldier1979 [14.2K]

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Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

$C( \dfrac{x+3}{2}, \dfrac{y+2}{2})$

Also, product of slope will be -1 .( Since, they are parallel )

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x = 2y - 1

So, $C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})$

Also, C satisfy given line :

$2\times ( \dfrac{2y + 2}{2}) + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}$

Also,

$x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}$

Therefore, the symmetric points is $A'(\dfrac{31}{5}, \dfrac{18}{5})$ .

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I Hope This Helped!!

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3 years ago

Read 2 more answers

If the order of a matrix A is 2×3 and order of AB is 2×4 then, find the order of matrix B.​

If the order of a matrix A is 2×3 and order of AB is 2×4 then, find the order of matrix B.