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gizmo_the_mogwai [7]
2 years ago
14

Which of the following is a pair of co -primes? (7, 9), (6, 12), (10, 14)

Mathematics
1 answer:
ella [17]2 years ago
4 0
A

7 and 9 are both prime numbers


Mark brainliest please
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Which one is right please explain
Kitty [74]
The correct answer would be B. Hope this helps, and please mark me the brainliest, we can be friends!!
5 0
3 years ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
5) A cab driver uses 36 gallons of gas in driving 529.2 miles. Find the
Sati [7]

Answer:

14.7 miles per gallon

Step-by-step explanation:

All you have to do is divide the number of miles by the number of gallons to find out how many miles are driven per gallon of gas. Hope I helped!

6 0
3 years ago
Read 2 more answers
Sarah left on the interstate at a speed of 65 mph. Her sister, Kendra, followed her on the same route, leaving 2
Olenka [21]

Answer:

26 Hours

Step-by-step explanation:

65 x 28 = 1820

70 x 26 = 1820

This is when they will be right next to each other

8 0
3 years ago
Read 2 more answers
Ivan has 4 hours of Music on his MP3 player Jazz makes up 1/6 of the total time how many hours of jazz are on Ivan's MP3 player
Crank
So theres 4 hours and 60min equals 1 hour, so multiply 4 by 60 to get 240, so theres 240 minutes of time on the mp3. So 1/6 of that total time (240min) was on jazz, so what you do is divide 240 by 6 to get 40, so every 1/6 is 40min. So you could say he spend 40min listening to jazz, or you could say he spent 2/3 of an hour listening to jazz
5 0
3 years ago
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