12x^2 + ax -20
if 3x + 4 is a factor of the expression above, what is the value of a?
2 answers:
i think that The correct answer is 1. It is given that one factor of the quadratic expression is 3x + 4. Thus, 12x2 + ax − 20 = (3x + 4)(mx + p), where a, m, and p are integers.
Answer:
1
Step-by-step explanation:
(3x + 4)(px + q) = 12x^2 + ax - 20
3px^2 + 3qx + 4px + 4q = 12x^2 + ax - 20
3px^2 = 12x^2
p = 4
4q = -20
q = -5
px + q = 4x - 5
(3x + 4)(4x - 5) =
= 12x^2 - 15x + 16x - 20
= 12x^2 + x - 20
= 12x^2 + ax - 20
ax = x
a = 1
You might be interested in
The ones that start with 6
If we multiply the top equation by -4 we can get rid of the x so:
-4x+20y=-12
4x-4y=12
Add these up
16y=0
Y=0
X=3
Answer:
3 ft 1 in
Step-by-step explanation:
As 12 in= 1 ft,
So, 3 in+ 10 in= 1 ft 1 in
Total= 2 ft + 1ft 1 in
= 3 ft 1 in