Answer:
Which of what following? There's no options.
Step-by-step explanation:
1 imperial foot has approximately 30.48 metric centimeters, and for one present we need 3 ft, or namely 3(30.48) cm, how many can we get from 102 cm? 102 ÷ 3(30.48) ≈ 1.1155, so barely just one present.
Since you are solving for diameter, and the equation is given to you, just isolate the variable for diameter (d).
(C)/π = (πd)/π
d = C/π is your formula you will use.
Plug in 56 for C
d = 56/π
d = ~17.825
~
Answer:
26.8
Step-by-step explanation:
Because 33.5 was the average of how many students were in a classroom (if there were 4 classrooms), then 33.5 is can somewhat be the average of how many students were in one classroom; 1/4 of the classrooms can hold an average of 33.5.
Total students that were divided into 4 classrooms :
33.5 × 4 = 134
So if there is 134 students that will be grouped into 5 different classrooms, divide 134 by 5 to find the average amount of students that will be grouped.
134 ÷ 5 = 26.8
So, the average amount of students that will be grouped if they were divided into 5 classrooms would be 26.8 .
Hope this helped !
