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balandron [24]
3 years ago
13

Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of ?

Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

y – 2 = (x – 3)

Step-by-step explanation:

because (3, 2) was the point used for the equation but turned negative because you need to make it negative for the equation. y - y1 =m(x - x1)

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Drawing Conclusions Consider the expression. 6 · 60 · 6–3 Which statements are true about the expression? Check all that apply.
Shtirlitz [24]

Answer:

6-3

Step-by-step explanation:

3 0
3 years ago
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Which of the following is the correct factorization of the polynomial below?
Masja [62]
I'm pretty sure that this one is the correct factorization of the polynomial above: <span>a) (3x+4)(9x^2-12x+16)</span>
6 0
3 years ago
Please help me with this question!
Harrizon [31]
6 pennies, 12 nickels, 8 dimes, 4 quarters = 30 coins

a) add the probability for drawing a dime and drawing a quarter together:
12/30 + 4/30 = 16/30 = 8/15
The probability is 8/15 or 53%

b) multiply the probability for drawing a penny and drawing a nickel:
6/30 x 12/30 = 72/900 = 2/25
The probability is 2/25 or 8%

c) multiply the probability for drawing quarters but take away one of the total coins and the amount of quarters each time:
4/30 x 3/29 x 2/28 = 24/24360 = 1/1015
The probability is 1/1015 or 0.099%
8 0
3 years ago
Find the midpoint of side EF. (4 points)
umka2103 [35]

Answer:

Midpoint of side EF would be (-.5,4.5)

Step-by-step explanation:

We know that the coordinates of a mid-point C(e,f) of a line segment AB with vertices A(a,b) and B(c,d) is given by:

e=a+c/2,f=b+d/2

Here we have to find the mid-point of side EF.

E(-2,3) i.e. (a,b)=(2,3)

and F(1,6) i.e. (c,d)=(1,6)

Hence, the coordinate of midpoint of EF is:

e=-2+1/2, f=3+6/2

e=-1/2, f=9/2

e=.5, f=4.5

SO, the mid-point would be (-0.5,4.5)

 

3 0
2 years ago
Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a^2 – 18 square units. Which i
netineya [11]

we know that

The area of the hexagon is equal to the sum of the areas of the six equilateral triangles

Let

x-------> area of one equilateral triangle

so

6x=24a^{2} -18

Divide by 6 both sides

x=4a^{2} -3 -------> area of one equilateral triangle

To find an equivalent expression for the area of the hexagon based on the area of a triangle, multiply the area of one equilateral triangle by 6

6*(4a^{2} -3)

therefore

the answer is

The equivalent expression is equal to 6*(4a^{2} -3)

6 0
3 years ago
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