Convert yards used for concrete to metric

The length of a rectangular plot of land is 10 yards more than its width. If the area of the land 600 square yards , find the di

vagabundo [1.1K]

Let the width of the rectangular plot of land be 'x' yards. Given that the length of the rectangular plot of land is 10 yards more than its width. So, width of the rectangular plot of land = (x + 10) yards. Also given that the area of the rectangular plot of land is 600 square yards. We know that, area of a rectangle = length * width That is, (x+10) * x = 600 x^2 + 10x = 600 x^2 + 10x - 600 = 0 x^2 + 30x - 20x -600 = 0 x(x + 30) - 20(x + 30) = 0 (x +30)(x -20) =0 Therefore, either (x + 30) = 0 or (x - 20) = 0 If x + 30 = 0, then x = -30 and If x - 20 = 0, then x = 20 Since 'x' represents the width of a rectangular plot of land it cannot be negative. Therefore, width of the rectangular plot of land = 20 yards length of the rectangular plot of land= x + 10 = 30 yards

5 0

3 years ago

A taxi charges $20 flat fee for the first 5 miles (even if it takes the rider one mile the cost is $20) and after that the addit

Free_Kalibri [48]

Ok so, we have the fact that 1.20 per mile Lets represent m as each additional mile so we have 1.20m which is That much per additional mile So For the first 5 functions we have f(1) = 20 f(2) = 20 f(3) = 20 f(4) = 20 f(5) = 20 Only for the first 5 miles though, since it is a flat fee. So for the additional miles we go back to what I said in the first Paragraph. 1.20m That is for additional miles, so that will be added to 20 So if you travel more than 5 miles the function looks like this: f(x) = 20 + 1.20m So the first 5 miles it is: f(x) = 20 For 7 mles the function would look like: f(7) = 20 + 1.20(2) It is a 2 because it is the additional mile, which is 2 hope this helps

7 0

3 years ago

Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"

Levart [38]

Answer:

$\huge\boxed{f(-1) = -7}$

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

$f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3$

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

$3(-1)^4 = 3$

WAIT! How is this possible? $-1^4 = -1$ (according to my calculator), and $3 \cdot -1 = -3$ , not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use $-2^2$ as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than being "-2 squared" - it's "the negative of of 2 squared."

Tying this back into our problem, the squared method would only be true if it looks like $-1^4$ . However, since we're substituting in -1, it looks like $(-1)^4$ , so the expression reads out as "-1 to the fourth."