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Degger [83]
2 years ago
7

HELPP ASaPP I’ll mark you as brainlister

Mathematics
2 answers:
dimulka [17.4K]2 years ago
8 0

Answer:

8.9

Step-by-step explanation:

nika2105 [10]2 years ago
5 0

Answer:

BC ≈ 8.9 units

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos36° = \frac{adjacent}{hypotenuse} = \frac{BC}{AB} = \frac{BC}{11} ( multiply both sides by 11 )

11 × cos36° = BC , then

BC ≈ 8.9 ( to the nearest tenth )

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How to solve (8x-30)+(6x+10)=180
lozanna [386]
Add the like terms. So I'll add the variables. 8x+6x is 14x. Now add whole numbers. 30+10 is 40. Our new expression we'll be 14x+40=180. Subtract 40 from 180. 180-40=140. Now we have the expression 14x=140. 140 divided by 14 is 10. So x is 10.
7 0
3 years ago
What is the best approximation of the solutions to the system to the nearest integer values?
Aleksandr-060686 [28]
The first number in the couplet is the distance along the x-axis (i.e. distance from the y-axis).  We can read 0.8 from the graph.
The second number is the distance along the y-axis (i.e.distance from the x-axis).  We can read 6.7 from the graph.

So approximately, we have the point as (0.8, 6.7).
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4 0
3 years ago
6.<br> -20 + -2m<br> Can u help me
stellarik [79]

Answer

Step-by-step explanation:

Replace all occurrences of

+

−

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1

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=

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4 0
3 years ago
A random sample of of 100 voters in a town is selected, and 24 are found to support an annexation suit. Find the 96% confidence
lbvjy [14]

Answer: 0.24 +/- 0.088 = (0.152, 0.328)

Step-by-step explanation:

The point estimate p is given by;

p= 24/ 100 = 0.24

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The solution for the given confidence interval is derived using the equation

p +/- z√(pq/n)

Where p = 0.24 q= 1-p = 0.76, n=100 z= 2.05

= 0.24 +/- 2.05√(0.24×0.76/100)

= 0.24 +/- 2.05(0.0427)

=0.24 +/- 0.088

= ( 0.152, 0.328)

6 0
3 years ago
How much greater was Maiami’s annual rainfall than Albany’s Albany 46.92 miami61.05
Ilia_Sergeevich [38]

Answer:

52.94

Step-by-step explanation:

61.06

-46.92

=52.94

<em>just</em><em> </em><em>subtract</em><em> </em><em>them</em><em> </em><em>like</em><em> </em><em>the</em><em> </em><em>.</em><em> </em><em>isn't</em><em> </em><em>even</em><em> </em><em>there</em><em>.</em>

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3 years ago
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