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nexus9112 [7]
3 years ago
10

You are riding in a taxi that charges a $10 flat fee, plus an additional $2 per

Mathematics
2 answers:
irakobra [83]3 years ago
7 0

Answer:

C= 2M + 10

Step-by-step explanation:

In this equation, we will calculate the total cost. So, we'll start off with "C =" Then, we know tat the charge is $2 per mile so we'll add it and make C = 2M. Then, it states that the flat fee is 10 dollars which makes the equation

C = 2M +10.

Alja [10]3 years ago
5 0

Answer:

C = 2M + 10

Step-by-step explanation:

To write this equation, we will use slope-intercept form: y = mx+b

In this problem, C is y and M is x, so: C = mM + b

m is the slope, or the rate of change, and b is the y-intercept.

The y-intercept in this problem is the $10 flat fee.

The rate of change is the additional $2 per mile.

Let's input these values into our equation:

C = 2M + 10

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Answer:

The fourth graph.

Step-by-step explanation:

We have f(x + 1)  so the x values will be increased by 1.

first value = 108 (when x  = 1)

next value = 108 * 2/3 = 72 (when x = 2)

next = 72 * 2/ 3= 48 (when x = 3)

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Answer two questions about Equations A and B: A. 5x = 20
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Step-by-step explanation:

Divide 20/5

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3 years ago
A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company prod
tekilochka [14]

Answer:

C) 515 hours.

D) 500 hours

c) sample 3

Step-by-step explanation:

1. Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample Service Life (hours)

1                2              3

495      525            470

500         515           480

505        505            460

<u>500         515             470        </u>

<u>∑2000     2060         1880</u>

x1`= ∑x1/n1= 2000/4= 500 hours

x2`= ∑x2/n2= 2060/4= 515 hours

x3`= ∑x3/n3= 1880/4=  470 hours

2. The mean of the sampling distribution of sample means for whenever service life is in control is 500 hours . It is the given mean in the question and the limits are determined by using  μ ± σ , μ±2 σ  or μ ± 3 σ.

In this question the limits are determined by using  μ ± σ .

3. Upper control limit = UCL = 520 hours

Lower Control Limit= LCL = 480 Hours

Sample 1 mean = x1`= ∑x1/n1= 2000/4= 500 hours

Sample 2 mean = x2`= ∑x2/n2= 2060/4= 515 hours

Sample 3 mean = x3`= ∑x3/n3= 1880/4=  470 hours

This means that the sample mean must lie within the range 480-520 hours but sample 3 has a mean of 470 which is out of the given limit.

We see that the sample 3 mean is lower than the LCL. The other  two means are within the given UCL and LCL.

This can be shown by the diagram.

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emmainna [20.7K]

Answer:

Door = 32 inches.

Step-by-step explanation:

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