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3 years ago

Help me lolol skixisknwnd

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

5 0

Answer:

x=300

Step-by-step explanation:

First you had to find the scale factor of the image to do that you would have to divide 325 by 13 resulting in 25 then you would multiple 12 times 25 resuliting in 300.

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- Given a test statistic of t= 3.018 of a left-tailed test with n= 13, use a 0.01 significance level

alina1380 [7]

Using the t-distribution, it is found that the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the mean of a given population is equal to 85, that is:

$H_0: \mu = 85$

We have a left-tailed test, hence, at the alternative hypothesis, it is tested if the mean of the population is less than 85, that is:

$H_1: \mu < 85$

<h3>What is the decision?</h3>

The test statistic is of t = -3.018.

Using a t-distribution calculator, with test statistic t = -3.018, 13 - 1 = 12 df and a significance level of 0.01, it is found that the p-value for a left-tailed test is of 0.0051.

The p-value is <u>less than 0.01</u>, hence the null hypothesis is rejected and the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

More can be learned about the t-distribution at brainly.com/question/16313918

5 0

2 years ago

The ratio of boys to girls in a class is 3:4. There are 35 students in the class. How many students are girls?

ASHA 777 [7]

There would be 20 girls

7 0

3 years ago

Read 2 more answers

Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

3 years ago

What is 689 divided by 24

Verdich [7]

The answer is 28.70
hope it help you
:)

6 0

3 years ago

Read 2 more answers

A forester measured 28 of the trees in a large woods that is up for sale. He found a mean diameter of 10.4 inches and a standard

JulsSmile [24]

Answer:

a) Attachment

b) 6 to 14.8 in

c) 2.5%

Step-by-step explanation:

Given:

- The mean is u = 10.4 in

- The standard deviation s.d = 4.4

- Sample size n = 28

Find:

- Choose the correct Normal model for tree diameters. A. B. C.

- What size would you expect the central 68% of all tree diameters to be?Using the 68-95-99.7 rule, the central 68% of the tree diameters are between ____ inches and _____ inches.

- About what percent of the trees should have diameters below 1.6 inches?

Solution:

- The central 68% lies within two s.d from mean.

10.4 + 1*4.4 = 14.8

10.4 - 1*4.4 = 6

Hence, the central 68% are between 6 and 14.8 inches.

- The central 95% lies within two s.d from mean.

10.4 + 2*4.4 = 19.2

10.4 - 2*4.4 = 1.6

- The central 95% are between 1.6 and 19.2 inches.

- Hence, P ( X < 1.6) = (1 - 0.95)/2 = 0.025 or 2.5%

5 0

3 years ago