Hello! the answers are (going across) 72/90 , 6/21 , 11/24 , 100/4 , 121/12 , 175/48
if u need me to explain how i got this, feel free to message me ! have a nice day:)<3
Answer:
1. 30
2. x<-72
3. 7b=63
4. x=3.2
5. 1/10
Step-by-step explanation:
1. Substitute a for 10
2(150/10)
2*15
30
2. Think of it like a normal equation
x/4<-18
x<-18*4
x<-72
3. 7b=63
4. 2.5x=8
x=3.2
5. 1/5*1/2= 1/10
Answer:

Step-by-step explanation:
we have

we know that



substitute the values in the expression above

Combine like terms

Can someone please help me too no one Answerss my question
Answer:
Step-by-step explanation:
The Taylor series at x=4 is

So,

Not too bad, eh?