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enyata [817]
3 years ago
14

Describe how you could show by adding aqueous sodium hydroxide and aqueous ammonia that a solution contained zinc ions.

Chemistry
1 answer:
Pavel [41]3 years ago
7 0

Answer:

*result with sodium hydroxide: white ppt of Zn(OH)2

*excess sodium hydroxide: Precipitate dissolves to form a COLOURLESS solution

*Result with Aqueous ammonia: White ppt of Zn(OH)2

*excess aqueous ammonia: Precipitate dissolves to form a COLOURLESS solution

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What is meant when one says that acetic acid is a stronger acid than benzoic acid?
kozerog [31]

Its the other way around actually. Benzoic acid is stronger than acetic acid because the electron-donating inductive effect (+I) by the alkyl group on acetic acid destabilise the conjugate base of acetic acid.

hope this helps :)

6 0
3 years ago
How many grams of CO are needed to produce 209.7 g Fe?<br><br> Fe2O3+3CO⟶3CO2+2Fe
kirill115 [55]

Answer:

157.8 g

Explanation:

Step 1: Write the balanced equation

Fe₂O₃ + 3 CO ⟶ 3 CO₂ + 2 Fe

Step 2: Calculate the moles corresponding to 209.7 g of Fe

The molar mass of Fe is 55.85 g/mol

209.7 g × 1 mol/55.85 g = 3.755 mol

Step 3: Calculate the moles of CO needed to produce 3.755 moles of Fe

The molar ratio of CO to Fe is 3:2. The moles of CO needed are 3/2 × 3.755 = 5.633 mol

Step 4: Calculate the mass corresponding to 5.633 moles of CO

The molar mass of CO is 28.01 g/mol.

5.633 mol × 28.01 g/mol = 157.8 g

4 0
3 years ago
How much energy moves onto the next level, in an energy pyramid
dybincka [34]
10% is normally how it works .
For example like 1,000 is the top the next level would be 100 then the next would be 10
7 0
3 years ago
Why are most household items made up of oxygen?
Alchen [17]
It is in our atmosphere
5 0
3 years ago
A chemistry student needs 60.0 g of 2-ethyltoluene for an experiment. He has available 1.5 kg of a 15.3% w/w solution of 2 ethyl
Mila [183]

Answer:

392 g

Explanation:

The given concentration tells us that<em> in 100 g of solution, there would be 15.3 g of 2-ethyltoluene</em>.

With that in mind we can<u> calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene</u>:

  • Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene
  • Mass of solution = 392 g
8 0
3 years ago
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