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3 years ago

L 1.1.4 Quiz: Calculating Heat

Chemistry

1 answer:

erma4kov [3.2K]3 years ago

3 0

Answer:

Aluminium is the right one

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Set up the ion formation equations, with ionization energy values for each electron in the valence layer, of the atoms of the ch

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Explanation:

Set up the ion formation equations, with ionization energy values for each electron in the valence layer, of the atoms of the chemical elements below: a) Na z=11 b) Ca z= 20 c) Sr z 38 d) Li z= 3 e) Cs z= 55 f) Be z= 43

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3 years ago

List three evidences of physical and chemical change. ( If you know only one or two please write them anyways please)

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Physical: ripping paper, braking a stick, cake batter mixing

Chemical: burning paper, spoiled milk, a penny turning green

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4 years ago

Which of the following statements is true? A. Sound waves are the only waves that reflect. B. An echo is a sound wave reflection

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B. An echo is a sound wave reflection

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3 years ago

How might the structure of an atom be modeled

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Explanation:

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3 years ago

Ammonium carbonate decomposes upon heating according to the following balanced equation:

Ugo [173]

Answer : The total volume of gas produced are, 11.5 L

Explanation :

First we have to calculate the moles of ammonium carbonate.

$\text{Moles of }(NH_4)_2CO_3=\frac{\text{Mass of }(NH_4)_2CO_3}{\text{Molar mass of }(NH_4)_2CO_3}$

Molar mass of $(NH_4)_2CO_3$ = 96.094 g/mol

$\text{Moles of }(NH_4)_2CO_3=\frac{11.9g}{96.094g/mol}$

$\text{Moles of }(NH_4)_2CO_3=0.124mol$

Now we have to calculate the moles of total gas.

The given balanced chemical reaction is:

$(NH_4)_2CO_3(s)\rightarrow 2NH_3(g)+CO_2(g)+H_2O(g)$

From the balanced chemical reaction we conclude that,

As, 1 mole of $(NH_4)_2CO_3$ react to give 4 mole of gas

So, 0.124 mole of $(NH_4)_2CO_3$ react to give $0.124\times 4=0.496$ mole of gas

Now we have to calculate the volume of gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of gas = 1.05 atm

V = Volume of gas = ?

n = number of moles = 0.496 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas = $24.0^oC=273+24.0=297.0K$

Putting values in above equation, we get:

$1.05atm\times V=0.496mole\times (0.0821L.atm/mol.K)\times 297.0K$

$V=11.5L$

Thus, the total volume of gas produced are, 11.5 L

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3 years ago