The correct answer is "greenhouse gases." Certain gases in the atmosphere, like carbon dioxide, nitrous oxide, and methane, absorb heat and prevent it from escaping into space. These gases are called greenhouse gases.
Answer:
You will have 19.9L of Cl2
Explanation:
We can solve this question using:
PV = nRT; V = nRT/P
<em>Where V is the volume of the gas</em>
<em>n the moles of Cl2</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is 273.15K assuming STP conditions</em>
<em>P is 1atm at STP</em>
The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:
63g * (1mol / 70.906g) = 0.8885 moles
Replacing:
V = 0.8885mol*0.082atmL/molK*273.15K/1atm
V = You will have 19.9L of Cl2
Answer:
A. 140,800 J
Explanation:
Specific heat of a material is defined as the amount of energy required to increase in 1°C 1kg of the material. <em>For wood there are required 1760J perkg per °C.</em>
The equation is:
Q = C*m*ΔT
<em>Where Q is heat in Joules,</em>
<em>C is specific heat (1760J/kg°C),</em>
<em>m is mass (2kg)</em>
<em>ΔT is change in temperature (50°C - 10°C = 40°C)</em>
Replacing:
Q = 1760J/kg°C*2kg*40°C
Q = 140800J
Right option is:
<h3>A. 140,800 J
</h3>
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3H2+N2→2NH3
here h2 H2 is limiting reagent
6moles of H2 will give 4moles of NH3
V of NH3 produced=22.4*4L
