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Wewaii [24]
3 years ago
8

Do you want to install the updates how?

Computers and Technology
1 answer:
Volgvan3 years ago
6 0

Answer:

output:

10

13

Explanation:

should be, may be, probably is

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The Synonyms submenu offers a list of synonyms for a word. Is it always a good idea to use whatever synonyms are presented on th
Ann [662]

Answer:

No

Explanation:

Synonyms are sometimes NEARLY the same. Not exactly the same. Therefore the meanings can change a bit. For example a synonym for "bad" is "careless."

"I think corn is bad."

and

"I think corn is careless." - this sentence wouldn't make sense.

That's why, no, you shouldn't ALWAYS use the synonym.

7 0
3 years ago
Write an application that accepts a word from a user and converts it to Pig Latin. If a word starts with a consonant, the Pig La
Scorpion4ik [409]

Answer:

Written in Python

word = input("Word: ")

if(word[0]=='a' or word[0]=='e' or word[0]=='i' or word[0] =='o' or word[0]=='u'):

     print(word+"ay")

else:

     a = word[1:]

     print(a+word[0]+"ay")

Explanation:

<em>The program was written in Python and I've added the explanation as an attachment; where I used comments as explanations</em>

Download txt
7 0
4 years ago
An information system report is an example of...
STatiana [176]

Answer:

a. data processing

b. data collection

c. data input

d. data output

Explanation:

An information system is a system used to filter, process, collect, distribute and create data.

Information system can be a work system whereby humans and machine perform processess using informations gathered, process it to solve the needs of their customers in the form of goods and services.

8 0
4 years ago
Write an application that accepts up to 20 Strings, or fewer if the user enters the terminating value ZZZ. Store each String in
notsponge [240]

Answer:

count = 20

i = 0

short_strings = []

long_strings = []

while(i<count):

   s = input("Enter a string: ")

   

   if s == "ZZZ":

       break

   

   if len(s) <= 10:

       short_strings.append(s)

   elif len(s) >= 11:

       long_strings.append(s)

   

   i += 1

choice = input("Enter the type of list to display [short/long] ")

if choice == "short":

   if len(short_strings) == 0:

       print("The list is empty.")

   else:

       print(short_strings)

else:

   if len(long_strings) == 0:

       print("The list is empty.")

   else:

       print(long_strings)

Explanation:

*The code is in Python.

Initialize the count, i, short_strings, and long_strings

Create a while loop that iterates 20 times.

Inside the loop:

Ask the user to enter a string. If the string is "ZZZ", stop the loop. If the length of the string is smaller than or equal to 10, add it to the short_strings. If the length of the string is greater than or equal to 11, add it to the long_strings. Increment the value of i by 1.

When the loop is done:

Ask the user to enter the list type to display.

If the user enters "short", print the short list. Otherwise, print the long_strings. Also, if the length of the  chosen string is equal to 0, print that the list is empty.

3 0
4 years ago
If you want an app to reach the largest possible audience, which two platforms should you use?
Papessa [141]

Android Studio for Android, and Xcode for Apple devices.

6 0
3 years ago
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