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konstantin123 [22]
3 years ago
14

Unlike radio frequency identification (RFID) tags, bar codes: Question 30 options: require a reader that tunes into a specific f

requency to determine the location of products. cannot be read using a handheld or pen-type scanner that reads and records data instantly. require direct line-of-sight scanning. increase data entry errors by 75 percent.
Computers and Technology
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

require direct line-of-sight scanning.

Explanation:

Unlike radio frequency identification (RFID) tags, bar codes require direct line-of-sight scanning. Meaning you need a device that can scan the bar code and the scanner needs to be directly pointing at the barcode without anything in the way. This is because bar codes work by embedding the information in a design of lines that need to be scanned to retrieve the information. If anything gets in the way it interrupts the scanning process and the data is not correctly transmitted. RFID tags on the other hand do not need a direct line of sight since the information is transferred through radiofrequency. This allows the data to be transferred without a line of sight and at a distance of up to 300ft.

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AP CSP - Write a program that takes 10 random numbers from 1 to 12 inclusively and averages them together.
Amanda [17]

Answer:

follows are the correct python code to this question:

import random as r#import random package as r

import statistics as s #import statistics package as s

l= r.sample(range(0,12),10)#defining l variable that use random function to store 10 random numbers

avg= s.mean(l)#defining avg variable for calculate average of l

print('List of random number are: ', l)#print list of random numbers

print("The random number Average is: ", avg)#print average value

Output:

List of random number are:  [4, 10, 6, 0, 3, 5, 1, 7, 11, 2]

The random number Average is:   4.9

Explanation:

In question 1:

In the given code, two packages are imported, which are "random and statistics", in which "random" is used to generate a random number, and "statistics" is used to calculate the average value.

In the code, the "l" variable is used, which uses a random function and store 10 random numbers, and an "avg" variable is defined that calculates the average value. In the last step, the print method is used that print number and its average value.

In question 2:

The given code is wrong because it only calls the "random" method, which is not defined.

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2 years ago
How many answer or point do I answer/need to sent message?
Grace [21]

I'm a little confused about the question, but if you're asking how many points you need to ask a question, the minimum is 10.


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3 years ago
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masha68 [24]

Answer: Please find below the answer along with explanation.

Explanation:

For  a given communication channel (for instance, a LAN segment using Ethernet ) the Bandwidth refers to the theoretical maximum data rate that the channel can support, for instance, 100 Mbps in a 100Base T network.

The throughput, instead, refers to the actual data rate achieved in a given communications channel, taking into account the different channel impairments.

For instance, in a LAN segment that uses the original Ethernet 802.3 standard (CSMA/CD), a frequent occurrence of collisions can take down the actual data rate from the theoretical 100 Mbps to a very lower figure, i.e., 5 Mbps.

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