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konstantin123 [22]
3 years ago
14

Unlike radio frequency identification (RFID) tags, bar codes: Question 30 options: require a reader that tunes into a specific f

requency to determine the location of products. cannot be read using a handheld or pen-type scanner that reads and records data instantly. require direct line-of-sight scanning. increase data entry errors by 75 percent.
Computers and Technology
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

require direct line-of-sight scanning.

Explanation:

Unlike radio frequency identification (RFID) tags, bar codes require direct line-of-sight scanning. Meaning you need a device that can scan the bar code and the scanner needs to be directly pointing at the barcode without anything in the way. This is because bar codes work by embedding the information in a design of lines that need to be scanned to retrieve the information. If anything gets in the way it interrupts the scanning process and the data is not correctly transmitted. RFID tags on the other hand do not need a direct line of sight since the information is transferred through radiofrequency. This allows the data to be transferred without a line of sight and at a distance of up to 300ft.

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Repeated execution of a set of programming statements is called repetitive execution.
Korolek [52]

Answer:

False

Explanation:

6 0
2 years ago
You would set a ___________ to prevent users from immediately changing their password several times in one day to return to the
Temka [501]

Answer:

The answer is (B) Maximum password age.

Explanation:

To prevent several changing of passwords by a user in a day, the maximum times a password can be rest within a day is normally set by  the system administrator.

The setting ensures the password is returned to the current settings of the password on the system for the user and prevents unnecessary changing of passwords in a day by user.

6 0
3 years ago
Read 2 more answers
Belvedere Street is parallel to St. Anthony Street. Davidson Street is perpendicular to River Street. River Street is parallel t
Sergio039 [100]

Answer:

Davidson street is perpendicular to Belvedere street

Explanation:

Belevedere is street is parallel to Anthony street which is parallel to Rivers street. Also Davidson street is perpendicular to River street which we already know is parallel to Belvedere street since it is parallel to St Anthony street therefore Davidson street is perpendicular to belverdere street as it is perpendicular to all other street listed:Rivers street and St Anthony street

6 0
3 years ago
- Consider the relation R = {A, B, C, D, E, F, G, H, I, J} and the set of functional dependencies F = { {B, C} -> {D}, {B} -&
Olenka [21]

Answer:

The key of R is {A, B}

Explanation:

A key can be seen as a minimal set of attributes whose closure includes all the attributes in R.

Given that the closure of {A, B}, {A, B}+ = R, one key of R is {A, B} But in this case, it is the only key.

In order for us to to normalize R intuitively into 2NF then 3NF, we have to make use of these approaches;

First thing we do is to identify partial dependencies that violate 2NF. These are attributes that are

functionally dependent on either parts of the key, {A} or {B}, alone.

We can calculate

the closures {A}+ and {B}+ to determine partially dependent attributes:

{A}+ = {A, D, E, I, J}. Hence {A} -> {D, E, I, J} ({A} -> {A} is a trivial dependency)

{B}+ = {B, F, G, H}, hence {A} -> {F, G, H} ({B} -> {B} is a trivial dependency)

To normalize into 2NF, we remove the attributes that are functionally dependent on

part of the key (A or B) from R and place them in separate relations R1 and R2,

along with the part of the key they depend on (A or B), which are copied into each of

these relations but also remains in the original relation, which we call R3 below:

R1 = {A, D, E, I, J}, R2 = {B, F, G, H}, R3 = {A, B, C}

The new keys for R1, R2, R3 are underlined. Next, we look for transitive

dependencies in R1, R2, R3. The relation R1 has the transitive dependency {A} ->

{D} -> {I, J}, so we remove the transitively dependent attributes {I, J} from R1 into a

relation R11 and copy the attribute D they are dependent on into R11. The remaining

attributes are kept in a relation R12. Hence, R1 is decomposed into R11 and R12 as

follows: R11 = {D, I, J}, R12 = {A, D, E} The relation R2 is similarly decomposed into R21 and R22 based on the transitive

dependency {B} -> {F} -> {G, H}:

R2 = {F, G, H}, R2 = {B, F}

The final set of relations in 3NF are {R11, R12, R21, R22, R3}

4 0
3 years ago
Every information systems (is) user has the right to a secure computing environment. this means that the
Arturiano [62]
<span>Every information systems (IS) user has the right to a secure computing environment. this means that the </span>organization should protect his/her computer and its files.
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3 years ago
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