C
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~Sequoyah! :-)
Answer:
that's standard form for slope
Step-by-step explanation:
have a nice day :)
(-3,-10).....slope(m) = 2
y - y1 = m(x - x1)
y - 3 = 2(x - 10)
Slope = (y₂- y₁) / (x₂- x₁)
Points C( 3, -5) and D (6, 0) compare to (x₁, y₁) and (x₂, y₂)
Slope = (0 - -5) / (6- 3) = (0+5) / (3) = 5/3
Slope = 5/3
Equation of line given a slope and point, y - y₁ = m(x - x₁)
m = 5/3, let point C( 3, -5) = (x₁, y₁)
y - - 5 = (5/3) (x - 3)
y + 5 = (5/3)(x - 3)
3(y + 5) = 5(x - 3)
3y + 15 = 5x - 15
3y = 5x - 15 - 15
3y = 5x - 30
Hence the equation of the line is 3y = 5x - 30
Answer:
Step-by-step explanation:
Given that the weights of bags filled by a machine are normally distributed with a standard deviation of 0.055 kilograms and a mean that can be set by the operator.
Let the mean be M.
Only 1% of the bags weigh less than 10.5 kilograms
i.e. P(X<10.5) = 0.01
corresponding Z value for P(Z<z) = 0.01 is -0.025
i.e. 10.5 = M-0.025(0.055)
Solve for M from the above equation
M = 
Rounding off we get
10.50 kgs
Mean weight should be fixed as 10.50 kg.