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3 years ago

Let f(x) = twenty-four over the quantity of 3 x minus two. Find f(-2

Mathematics

2 answers:

Anettt [7]3 years ago

7 0

Answer:

B -3

Step-by-step explanation:

Just took the test and got 100%

bija089 [108]3 years ago

4 0

$f(x)=\frac{24}{3x-2}\\\\f(-2)=?\\
Subtitude\ x=-2\\
f(-2)=\frac{24}{3*(-2)-2}=\frac{24}{-6-2}=\frac{24}{-8}=-3\\\\
Solution\ is\ f(-2)=-3.$

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Is the square root of 53 a irrational or rational number

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2 years ago

Read 2 more answers

the vertices of PQR are P(-5,1), Q(-4,6), and R(-2,3), graph P"Q"R" after a composition of the transformations in the order they

horsena [70]

SOLUTION

We are told to translate; (x, y) to (x -8, y). This means we have to add - 8 to each value of x in P(-5,1), Q(-4,6), and R(-2,3).

In P(-5,1), x = -5 and y = 1

In Q(-4,6), x = -4 and y = 6 and

In R(-2,3), x = -2 and y = 3

$\begin{gathered} P(-5,\text{ 1) translates to (-5 -8, 1) }\rightarrow P^i(-13,\text{ 1)} \\ Q(-4,\text{ 6) translates to (-4 -8, 6) }\rightarrow Q^i(-12,\text{ 6)} \\ R(-2,\text{ 3) translates to (-2 -8, 3) }\rightarrow R^i(-10,\text{ 3)} \end{gathered}$

For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.

$\begin{gathered} At\text{ K = 2, }P^i(-13,\text{ 1) }\rightarrow\text{ }2(-13,\text{ 1) }\rightarrow\text{ }P^{ii}(-26,\text{ 2)} \\ Q^i(-12,\text{ 6) }\rightarrow\text{ }2(-12,\text{ 6) }\rightarrow\text{ Q}^{ii}(-24,\text{ 12)} \\ R^i(-10,\text{ 3) }\rightarrow\text{ }2(-10,\text{ 3) }\rightarrow\text{ R}^{ii}(-20,\text{ 6)} \end{gathered}$

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1 year ago

Assume that the weights of quarters are normally distributed with a mean of 5.67 g and a standard deviation 0.070 g. A vending m

Anuta_ua [19.1K]

Answer:

A) 1.96%

Step-by-step explanation:

You need to know the band between 5.48 g and 5.82 g, the mean is 5.67 g and the standard deviation is .0.070 g, with that information you can calculate the percentage to the left of the mean and the percentage to the right of the mean and add them.

To know its percentage you have to calculate the z score for both values.

$z = \frac{x-\mu}{\sigma}$

x is the value being evaluated

μ is the mean

σ is the standard deviation

For 5.48 g:

$z = \frac{5.48-5.67}{0.070} =-2.714$

and is equivalent to 0.0034

For 5.82 g:

$z = \frac{5.82-5.67}{0.070} = 2.143$

and is equivalent to 0.9838

Those numbers mean that the percentage below 5.48 is equivalent to the 0.34% of the values and the percentage below 5.82 is equivalent to 98.38% of the values. Then the percentage rejected is the percentage above 5.82, 100 - 98.38 = 1.62% plus the percentage below 5.48, 0.34%.

Percentage rejected = 1.62% + 0.34% = 1.96%

7 0

3 years ago

Given that f(x) = 6x +1, find (f of)(-2). (f of)(-2) | (Simplify your answer.)

irakobra [83]

Answer:

(f of)(-2) = -65

Step-by-step explanation:

Set up (f of)(-2)

(f o f)(-2) = f(f(-2))

Once you get (fof)(-2) you then have f(#)

f(6(-2) + 1) = f(-11)

6(-11) + 1 = -66 + 1 = -65

8 0

3 years ago