<span> First, reduce the fraction to lowest terms, e.g. 8/6 = 4/3.
Look at the denominator. Split it into its prime factors. If its prime
factors only consist of 2's and 5's, then it will be terminating.
Examples:
16 = 2 x 2 x 2 x 2, so terminating
25 = 5 x 5, so terminating
2000 = 2 x 1000 = 2 x (2 x 5) x (2 x 5) x (2 x 5), so terminating
12 = 2 x 3, so repeating (has prime factor 3, which is not 2 or 5)
13 = 13, so repeating (has prime factor 13, which is not 2 or 5) Hope this helps!!
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You would first make the fractions improper (making the numerator bigger then the denominator) in order to do that times the denominator with the whole number and add the numerator.
Ex) 3*8 = 24 + 5 = 29/8
Then you would add both of the improper fractions
Answer:
Yes thats correct
Step-by-step explanation:
Step-by-step explanation:
y = ax + b
I see already the result (y = x/10 × 1/6), but let's go in formally.
we have multiple function points to use to officially calculate a and b.
1/6 = a×10 + b
2/3 = a×40 + b
5/6 = a×50 + b
1 2/3 = a×100 + b
let's e.g subtract equation 1 from equation 3.
4/6 = a×40 + 0
a = 4/40 / 6 = 4 / 240 = 1/60
1/6 = 10/60 + b
1/6 = 1/6 + b
b = 0
so, the function is
y = x/60
x = 25
y = 25/60 = 5/12 cups
Answer:
(-5/2, 3/2)
Step-by-step explanation:
[(-5.5+.5)/2, (9.1-6.1)/2)} = (-5/2, 3/2)
