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3 years ago

12

When the transmogrifiers are made at the factory, they move along a conveyer belt. Every 8th transmogrifier gets a blue control

panel, every 3rd transmogrifier comes in green, and every 4th transmogrifier comes with a genuine Spaceman Spiff autographed photo. If 150 transmogrifiers come off of the conveyer belt, how many will have a blue control panel, be green, and come with a Spaceman Spiff autographed photo?

2 answers:

Vladimir79 [104]3 years ago

5 0

Answer:

50 green

Step-by-step explanation:

19 blue

38 spaceman

MaRussiya [10]3 years ago

4 0

Answer:

Blue - 18, green - 50, with photo - 37

Step-by-step explanation:

<u>Total number = 150</u>

Blue = 150/8 = 18 (integer part)
Green = 150/3 = 50
Spaceman Spiff autograph = 150/4 = 37 (integer part)

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Thepotemich [5.8K]

Answer:

√(36+9) = √45 = 6.7 this is the answer, just estime it

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3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

True [87]

Answer:

17

Step-by-step explanation:

m<1 = (4x + 2)

m<3 = (5x - 15)

To find the value of x, we need to generate an equation.

<1 and <3 are vertical angles. Vertical angles are congruent. Therefore:

m<1 = m<3

(4x + 2) = (5x - 15)

Use this equation to solve for x

4x + 2 = 5x - 15

Subtract 5x from both sides

4x + 2 - 5x = 5x - 15 - 5x

-x + 2 = -15

Subtract 2 from both sides

-x + 2 - 2 = -15 - 2

-x = -17

Divide both sides by -1

x = 17

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3 years ago

Which property of inequality should you use to solve 3x ≤ 27?

lord [1]

division property would help you solve this inequality

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3 years ago

M/18=24/15 <br>how do I do this problem?

GrogVix [38]

M/18 = 24/15
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3 years ago