The diagram filled out if you look it up I hope that can help you
I believe runoff would be the answer.
Answer:
Explanation:
The observed frequency of the double crossovers (DCOs) is 20/1000, or 0.02. If there is no interference then this will be the same as the expected, which is just the product of the single crossover frequencies, that is, SCO frequency (a-b) x SCO freq. (b-c) = 0.02.
(a) Any combination of map distances whose product (a-b) x (b-c) = 0.02 is possible. However, three are most likely:
a 20 mu b 10 mu c
a 10 mu b 20 mu c
a 14.14 mu b 14.14 mu c
(b) The distances would be exactly the same.
(c) The expected number of DCO progeny would be 17.
<span>The role of a restriction enzyme is essentially used to cut a single gene from a larger piece of DNA. It has a very important role to play in experiments investigating cloning, and in the construction of particular DNA molecules.</span>
