Answer:
x≤9/2
Step-by-step explanation:
8x+15≤51
Subtract 15
8x+15-15≤51-15
8x+≤36
Divide by 8
8x/8≤36/8
x≤9/2
The possible values (L,W): (1,7),(2,6),(3,5),(5,3),(6,2),(7,1)
The slope of the line connecting two points (<em>a</em>, <em>b</em>) and (<em>c</em>, <em>d</em>) is
(<em>d</em> - <em>b</em>) / (<em>c</em> - <em>a</em>)
i.e. the change in the <em>y</em>-coordinate divided by the change in the <em>x</em>-coordinate. For a function <em>y</em> = <em>f(x)</em>, this slope is the slope of the secant line connecting the two points (<em>a</em>, <em>f(a)</em> ) and (<em>c</em>, <em>f(c)</em> ), and has a value of
(<em>f(c)</em> - <em>f(a)</em> ) / (<em>c</em> - <em>a</em>)
Here, we have
<em>f(x)</em> = <em>x</em> ²
so that
<em>f</em> (1) = 1² = 1
<em>f</em> (1.01) = 1.01² = 1.0201
Then the slope of the secant line is
(1.0201 - 1) / (1.01 - 1) = 0.0201 / 0.01 = 2.01
Answer:
75
Step-by-step explanation:
Scores for his first tests were 65, 67, 69.
Rate of change: +2
y=2x+63; 63 is the 0th test he took, his first test was 65, so 65-2=63. 2x is the rate of change, his tests scores increase by 2 each time.
x=6, 6th test score
y=2(6)+63
y=12+63
y=75
So, on his 6th test he will get a score of 75
A square again
Lets take a is side of a square.
if u take parts of square from mid point and measure distance or length of any sides that would be a/2
then use Pythagorean theorem to solve hypotenuse u will get all length of small quadrilateral a/√2.same for all sides.
I see that will be square again
