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aleksandr82 [10.1K]
2 years ago
10

(1+sinx/cosx)+(cosx/1+sin)

Mathematics
1 answer:
Licemer1 [7]2 years ago
5 0

( 1 + sinx / cosx ) + ( cosx / 1 + sinx ) =

_________________________________

(1 + sinx)(1 + sinx)/cosx(1 + sinx)

+

(cosx)(cosx)/(1 + sinx)(cosx) =

_________________________________

(1 + sinx)^2 /cosx(1 + sinx)

+

(cosx)^2/cosx(1 + sinx) =

_________________________________

1 + 2sinx + sin^2 x/cosx(1 + sinx)

+

cos^2 x/cosx(1 + sinx) =

_________________________________

1 + sin^2 x + cos^2 x + 2sinx / cosx(1 + sinx) =

<h2>Hint : </h2><h2>Sin^2 x + Cos^2 x = 1</h2>

1 + 1 + 2sinx / cosx(1 + sinx) =

2 + 2sinx / cosx(1 + sinx) =

2(1 + sinx)/cosx(1 + sinx) =

( 1 + sinx) simplifies from the face and the denominator of the fraction

2/cosx

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