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Explanation:
An object is attached to the spring and then released. It begins to oscillate. If it is displaced a distance 0.125 m from its equilibrium position and released with zero initial speed. The amplitude of a wave is the maximum displacement of the particle. So, its amplitude is 0.125 m.
After 0.800 seconds, its displacement is found to be a distance 0.125 m on the opposite side. The time period will be,
We know that the relation between the time period and the time period is given by :
f = 0.625 Hz
So, the frequency of the object is 0.625 Hz. Hence, this is the required solution.
Explanation:
Particle moving in a circular path with a constant speed.
