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3 years ago

CAN U HELP PLZZ? ;(

Physics

1 answer:

Ahat [919]3 years ago

7 0

Answer would be D sorry if wrong

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cestrela7 [59]

family 16 cause i said so XD

5 0

3 years ago

The amount of energy the body uses when at rest is referred to as _____.

Nesterboy [21]

The answer is Basal Metabolic Rate. It is the total amount of energy expressed in calories that an individual needs to keep the body working at rest. Some of those progressions are blood circulation, breathing, cell growth, controlling body temperature, nerve and brain function, and tightening of muscles.

8 0

3 years ago

a train travles at a speed of 30m/s. the train starts at an initial position of 1000 meters and travels for 30 seconds. what is

ycow [4]

Answer:

1900 meters

Explanation:

30m/s x 30 second = 900 meters

+ 1000 meters starting position

= 1900meters

5 0

3 years ago

If 100 grams of vinegar and 5 grams of baking soda are poured in a container, a small amount of gas will be produced. What will

Anit [1.1K]

It will be a little bit less because of evaporation i learned that in third grade and your in high school that is sad

5 0

3 years ago

Consider an insulating sphere of radius 6 cm surrounded by a conducting sphere of inner radius 18 cm and outer radius 26 cm. Fur

dimulka [17.4K]

Answer:

$-1.7908787542\times 10^{-9}\ C$

$3.4260289211\times 10^{-9}\ C$

$1.7908787542\times 10^{-9}\ C$

$1.6351501669\times 10^{-9}\ C$

Explanation:

r = Radius

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

Electric field is given by

$E=-\dfrac{kq}{r^2}\\\Rightarrow q=-\dfrac{Er^2}{k}\\\Rightarrow q=-\dfrac{1610\times 0.1^2}{8.99\times 10^9}\\\Rightarrow q=-1.7908787542\times 10^{-9}\ C$

The charge is $-1.7908787542\times 10^{-9}\ C$

$Q+q=\dfrac{Er^2}{k}\\\Rightarrow Q=\dfrac{Er^2}{k}-q\\\Rightarrow Q=\dfrac{120\times 0.35^2}{8.99\times 10^9}-(-1.7908787542\times 10^{-9})\\\Rightarrow Q=3.4260289211\times 10^{-9}\ C$

The charge is $3.4260289211\times 10^{-9}\ C$

The charge inside will have the polarity changed

$q=+1.7908787542\times 10^{-9}\ C$

Outside the charge will be

$3.4260289211\times 10^{-9}-1.7908787542\times 10^{-9}\\ =1.6351501669\times 10^{-9}\ C$

3 0

3 years ago