3 years ago

115 - 12

Mathematics

1 answer:

faltersainse [42]3 years ago

5 0

Answer:

by my calculator I got 2.25

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Can someone please help me??? a is 3/4 b is -8 c is -2 d is 3

Pavel [41]

Answer:

-b[a + (c-d)^2]

-(-8)[3/4 + (-2 -3)^2]

8 [3/4 + (-5)^2]

8 [3/4 + 25]

8 [25.75]

206

5 0

3 years ago

Read 2 more answers

(2x³+4x²-x+8) / (x² + 3x + 2)

a_sh-v [17]

$\dfrac{2x^3+4x^2 -x+8}{x^2 +3x+2}\\\\\\=\dfrac{2x^3+6x^2+4x-2x^2-6x-4+x+12}{}\\\\=\dfrac{2x(x^2 +3x+2)-2(x^2 +3x+2)+x+12}{x^2 +3x+2}\\\\\\=\dfrac{2x(x^2+3x+2)}{x^2 +3x +2 }- \dfrac{2(x^2 +3x +2)}{x^2 +3x +2 } + \dfrac{x+12}{x^2 +3x+2}\\\\\\=2x-2 + \dfrac{x+2}{x^2 +3x +2}\\\\\\=2x-2 + \dfrac{x+12}{x^2 +2x +x +2}\\\\\\=2x-2 + \dfrac{x+12}{x(x+2) + x+2}\\\\\\=2x-2 + \dfrac{x+12}{(x+1)(x+2)}\\$