Question

Can someone please help me??? a is 3/4 b is -8 c is -2 d is 3

Answer 1

Answer:

-b[a + (c-d)^2]

-(-8)[3/4 + (-2 -3)^2]

8 [3/4 + (-5)^2]

8 [3/4 + 25]

8 [25.75]

206

Answer 2

Answer: 206

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Work Shown:

a = 3/4

b = -8

c = -2

d = 3

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c-d = -2-3 = -5

(c-d)^2 = (-5)^2 = 25

a+(c-d)^2 = 3/4 + 25 = 3/4 + 100/4 = 103/4

-b * [ a + (c-d)^2 ] = -(-8)*103/4 = 8*103/4 = (8/4)*103 = 2*103 = 206

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Another way to show the steps could be

$-b[a+(c-d)^2]\\\\-(-8)\left[\frac{3}{4}+(-2-3)^2\right]\\\\8\left[\frac{3}{4}+(-5)^2\right]\\\\8\left(\frac{3}{4}+25\right)\\\\8\left(\frac{3}{4}+\frac{100}{4}\right)\\\\8\left(\frac{3+100}{4}\right)\\\\8\left(\frac{103}{4}\right)\\\\\frac{8}{4}*103\\\\2*103\\\\206$

Which is more or less the same thing as the previous section.

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So ultimately,

$-b[a+(c-d)^2] = 206$

when a = 3/4, b = -8, c = -2, and d = 3.