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tankabanditka [31]
2 years ago
5

Jeremy is taking a photography class, but he doesn't own a camera. The class organizers will rent him a camera for $6 per day. J

eremy can spend up to $50 for the class, but he has to pay $15 to register for the class as well as rent the camera. The number of days, d, that Jeremy can rent the camera is represented by the inequality 6d + 15 < 50. Select the number of days Jeremy can rent the camera with the money he has. A. 5 B. 6 C. 8 D. 9 E. 10
Mathematics
1 answer:
OlgaM077 [116]2 years ago
4 0
He can rent it for 5 days, you can solve this by subtracting the $15 flat rate from his $50, then dividing the remaining 35 by 6, leaving you with 5.8 which in this situation makes the answer 5
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Step-by-step explanation:

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John is considering accepting one of two sales positions. ABC Company offers a yearly salary of $45,000. XYZ Company offers a ye
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Answer:  Amount of sales s = $6240 is the salary at ABC company is greater than at XYZ company.

Step-by-step explanation:

Since we have given that

Annual salary of ABC company = $45000

Annual salary of XYZ company = $38000

Rate of commission = 2%

Amount of salary after commission at XYZ company would be

\dfrac{100+2}{100}\times 38000\\\\=\dfrac{102}{100}\times 38000\\\\=1.02\times 38000\\\\=38760

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45000-38760\\\\=\$6240

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3 0
4 years ago
13. A certain town with a population of 100,000 has 3 newspapers: I, II, and III. The proportions of townspeople who read these
Lina20 [59]

Answer:

24,000 people read only one newspaper

12,000 people read at least two newspapers

11,000 people read at least one morning paper plus an evening paper.

64,000 people do not read any newspapers.

10,000 people read only one morning paper and one evening paper.

Step-by-step explanation:

The problem states that:

- 10 percent of the population reads the newspaper I = 10,000

- 8 percent of the population reads the newspaper I and II = 8,000

- 1 percent of the population reads the newspaper I and II an III = 1,000

- 30 percent of the population reads the newspaper III = 30,000

- 2 percent of the population reads the newspaper I and III = 2,000

- 5 percent of the population reads the newspaper III = 5,000

- 4 percent of the population reads the newspaper II and III = 4,000.

Then we have to build the Venn diagram for this: I am going to call

- A the people that read the newspaper I

- B the people that read the newspaper II

- C the people that read the newspaper III

We start this from the people that read each newspaper

A \cap B \cap C = 1,000 - 1,000 people read each newspaper

The people that read only I and II are the number of people that read I and II minus the number of people that read I, II and III. So:

A \cap B = 8,000 - A \cap B \cap C = 8,000 - 1,000 = 7,000

It applies for I and III

A \cap C = 2,000 - A \cap B \cap C = 2,000 - 1,000 = 1,000

And for II and III

B \cap C = 4,000 - A \cap B \cap C = 4,000 - 1,000 = 3,000

The problem states that 10,000 people read the newspaper I, so:

A + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 10000 where A is the number of people that read only the newspaper I. So:

A + 7,000 + 1,000 + 1,000 = 10,000

A + 9,000 = 10,000

A = 1,000

30,000 read the newspaper II, so:

B + (A \cap B) + (B \cap C) + (A \cap B \cap C) = 30,000

B + 7,000 + 3,000 + 1,000 = 30,000

B + 11,000 = 30,000

B = 19,000

5,000 read the newspaper III, so:

C +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 5,000

C + 1,000 + 1,000 + 1,000 = 5,000

C = 2,000

The answers:

a) Find the number of people who read only one newspaper

A + B + C = 1,000 + 21,000 + 2,000 = 24,000

24,000 people read only one newspaper

b) How many people read at least two newspapers

(A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 7,000 + 1,000 + 3,000 + 1,000 = 12,000

12,000 people read at least two newspapers

If I and III are morning papers and II is an evening paper, how many people read at least one morning paper plus an evening paper?

(A \cap B) + (B \cap C) + (A \cap B \cap C) = 7,000 + 3,000 + 1,000 = 11,000

11,000 people read at least one morning paper plus an evening paper.

How many people do not read any newspapers?

There is 100,000 people in the town.

So, the number of people that does not read any newspaper is:

100,000 - (A + B + C + (A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C)) = 100,000 - 36,000 = 64,000

64,000 people do not read any newspapers.

How many people read only one morning paper and one evening paper?

(A \cap B) + (B \cap C) = 7,000 + 3,000 = 10,000

10,000 people read only one morning paper and one evening paper.

3 0
3 years ago
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