Answer:
The pressure exerted on the table due to the book is 200 N/m².
Explanation:
The pressure exerted on the table due to the book is 200 N/m².
The given parameters;
mass of the book, m = 400 g = 0.4 kg
dimension of the table, = 0.10m x 0.20 m.
gravitational field strength g = 10 N/kg.
The area of the table is calculated as follows;
A = 0.1 x 0.2 = 0.02 m²
The pressure exerted on the table due to the book is calculated as follows; where;
F is the force of the book due to its weight
Thus, the pressure exerted on the table due to the book is 200 N/m².
Is there a graph or a picture to go along with it? it would be easier for me to answer :)
Answer:
(15/17 = sin ∠ JLK)
(first option listed)
Explanation:
the "sin ∠ JLK" is what we can simply think of as the inside measurement of angle/corner L. (L is the letter in the middle of ∠ JLK , and if you imagine drawing a line from J to L to K, you would see that the only angle you formed both sides of is corner L)
so, we are looking for the sin of L.
(SOH CAH TOA)
we know that
sin = opposite / hypotenuse
However, we do not have the opposite value of this triangle <em>yet. </em>
-----
we can solve the length of the opposite side with the Pythagorean theorem:
a² + b² = c²
8² + b² = 17²
64 + b² = 289
- 64 - 64
b² = 225
√b² = √225
b = 15
----
so, to solve for sin L,
(sin = opposite / hypotenuse)
we should divide the opposite (15) over the hypotenuse (17)
so, 15 / 17 = sin L
(15/17 = sin ∠ JLK)
I think the answer is making a bechamel sauce
