On a coordinate plane, solid circles appear at the following points: (negative 3, negative 3), (negative 3, 2), (1, 1), (2, nega
tive 2), (3, 4), (4, negative 2). Which ordered pair could be removed so that the set of ordered pairs is a function?
2 answers:
Answer:
The real answer would be (-3,2)
Step-by-step explanation:
Hope This Helps :)
Brainliest......?
Answer:
ITS (3-2.) Thank me later
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I think -3 because 3(2) = 6 (3-6= -3)
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n=15
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7+(4+6)=7+n
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22=7+n
22-7=n
15=n
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